Linear Momentum and Its Conservation

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SUMMARY

The discussion centers on calculating the momentum of a 3.00-kg particle with a velocity of (3.00i - 4.00j) m/s. The x component of momentum is determined to be 9.00 kg*m/s, while the y component is -12.00 kg*m/s. To find the magnitude of the momentum, the user is advised to apply the Pythagorean theorem, which involves calculating the square root of the sum of the squares of the x and y components.

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Joyci116
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Homework Statement


A 3.00-kg particle has a velocity of (3.00i-4.00j)m/s. (a)Find its x and y components of momentum. (b) Find the magnitude and direction of its momentum.


Homework Equations


p=mv


The Attempt at a Solution


For part a, I found that the x and y components of momentum is (9.00i-12.00j)kg*m/s. But I am having trouble with the magnitude and direction. I was told to pythag it, but I am still not clear on what to do.

Thank you.
 
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Joyci116 said:

Homework Statement


A 3.00-kg particle has a velocity of (3.00i-4.00j)m/s. (a)Find its x and y components of momentum. (b) Find the magnitude and direction of its momentum.


Homework Equations


p=mv


The Attempt at a Solution


For part a, I found that the x and y components of momentum is (9.00i-12.00j)kg*m/s. But I am having trouble with the magnitude and direction. I was told to pythag it, but I am still not clear on what to do.

Thank you.

Rather than say :"the x and y components of momentum is (9.00i-12.00j)kg*m/s."

Can you separately say

The x component is : ...
The Y component is : ...
 
Okay.
 

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