Linear momentum conservation vs mecanical energy conservation

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SUMMARY

The discussion centers on the principles of linear momentum conservation and mechanical energy conservation during a collision between two balls, A and B. When ball A (mass ma) collides with ball B (mass mb) initially at rest, the linear momentum conservation formula is applied, yielding the final velocity v' as v' = ma*v/(ma + mb). In contrast, applying mechanical energy conservation leads to an incorrect result, v' = v (ma/(ma + mb))^(1/2), indicating energy dissipation during the collision. The conversation highlights that for the two balls to move together post-collision, they must stick, suggesting an inelastic collision rather than an elastic one.

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jaumzaum
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A ball A (mass ma) with initial velocity v colides with a ball B (mb) initially stopped. A and B gets the same direction/velocity v', Calculate v'

By linear momentum conservation
ma.v = (ma + mb).v'
v' = mav(ma + mb)

But by mecanical energy conservation

ma.v²/2 = (ma + mb).v'²/2
v' = v (ma/(ma + mb))^(1/2), which is wrong

Why we can't use mecanical energy conservation, is there a energy dissipation?
 
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jaumzaum said:
A ball A (mass ma) with initial velocity v colides with a ball B (mb) initially stopped. A and B gets the same direction/velocity v', Calculate v'
...
Why we can't use mecanical energy conservation, is there a energy dissipation?

Well, for A and B to get the same direction/velocity v' after the collision, don't they have to stick?

Does that sound like an elastic collision?
 

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