# Linear motion: a runner with two accelerations: 1 constant other not

## Homework Statement

Problem 3.7 Suppose that motion studies of a runner show that the maximum speed he
can maintain for a period of about 10 s is 12 m/s. If in a 100-m dash this runner
accelerates with constant acceleration until he reaches this maximum speed and then
maintains this speed for the rest of the race, what acceleration will he require if his total
time is 11 s?

## Homework Equations

a = v2/(22v - 200)

## The Attempt at a Solution

a = 2.25 m/s2

I've read through the solution. What I don't understand stand, however, is why v here would be the 12 m/s value. Sure, that's the velocity given, but how and why should I know to use 12 m/s? Why do I plug that into the relevant equation? I could say, sure, because it's the only velocity value given, but why that particular value?

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Well,
Acceleration is based on how much velocity needs to be attained. Velocity itself is determined as distance/time. So either you need to plug in the velocity or the date and time to arrive at an acceleration value!

rl.bhat
Homework Helper
He reaches the maximum velocity in time t1 with acceleration a. He covers the remaining distance in time (t - t1) with maximum velocity.
Use the time velocity graph to find the total displacement.
S = 1/2*t1vMax + vmax*(t - t1).
t and vmax is given. Find t1 ,and hence find acceleration.

CWatters
Homework Helper
Gold Member
linear motion: a runner with two accelerations: 1 constant other not
In case it's not obvious the title is wrong..

The runner first accelerates and then continues at constant velocity.

Last edited:
CWatters