A cyclist starts at the top of a straight slope with an initial velocity of 3.00m/s. Five seconds later, she is at the bottom of the incline, having traveled 50.0m. Find her velocity at the bottom of the hill and her acceleration, assuming it to be constant.
[tex]\Delta[/tex]x= V0 + .5at2
The Attempt at a Solution
I tried to find the acceleration first.
a= (2*[deltaX - V-initia]l)/ T2
I keep getting 3.76 as the acceleration but the books answer is 2.80m/s2
Thanks in advanced!