- #1

SpaceW

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## Homework Statement

A person is standing over a well and drops a rock. After 2.4 seconds he hears a rock splashing into the water. Take the speed of sound to be 300m/s and calculate the depth of the well.

## Homework Equations

x=v/t for constant velocity

x=1/2at^2 for accelerated motion

## The Attempt at a Solution

I tried this solving by taking t1=x/v x is depth of well and v speed of sound and also t2=(2x/g)^1/2

t1+t2=2.4 but i keep getting x to be 104.56 meters which can't be right although it seems all my steps are conclusive. Substituted t1 and t2 took p=x^1/2 and solved quadratic equation for p and god 10.4 m which goes to 104 m = x which is not right. What do you think is wrong?