1. The problem statement, all variables and given/known data A person is standing over a well and drops a rock. After 2.4 seconds he hears a rock splashing into the water. Take the speed of sound to be 300m/s and calculate the depth of the well. 2. Relevant equations x=v/t for constant velocity x=1/2at^2 for accelerated motion 3. The attempt at a solution I tried this solving by taking t1=x/v x is depth of well and v speed of sound and also t2=(2x/g)^1/2 t1+t2=2.4 but i keep getting x to be 104.56 meters which cant be right although it seems all my steps are conclusive. Substituted t1 and t2 took p=x^1/2 and solved quadratic equation for p and god 10.4 m which goes to 104 m = x which is not right. What do you think is wrong?