Linear Thermal expanion what is the formula we use?

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The discussion centers on calculating the final length of an object undergoing linear thermal expansion. The relevant formula is Lf = Li(1 + αΔT), where Lf is the final length, Li is the initial length, α is the linear coefficient of expansion, and ΔT is the change in temperature. Given an initial length of 3.0 m, a linear coefficient of 1.2 x 10^-5, and a temperature change from 30 degrees to 55 degrees, the calculation should yield the correct final length. Some participants initially miscalculated the final length, highlighting the importance of using the correct initial values and formula. Understanding and applying the linear thermal expansion formula is crucial for accurate results.
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Linear Thermal expanion! what is the formula we use?

Homework Statement


I have been given a linear coefficient which 1.2*10^-5 of something
i have been given the initial temperature of 30 degrees and final temperature of 55 degrees
I have been given that initial length is 3.0 m

I am trying to find the unknown final length ?



Homework Equations


please what's the relevant equation i need to use


The Attempt at a Solution

 
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try extension=L\alpha T
 


im sorry which one is extension

i used one forumula and i got 50

it was Final lenght= a Lenghts (final temp -initial temp) + initial lenght
thus final length = 2.0 m (initial lenght) *( 45 deg-20 deg) + 2.0 m
= 50 meters

is this right approach ?
 


In then problem the initial length is 3 m.
The relevant equation is
Lf = Li( 1 + alpha*change in temperature) where alpha is the coefficient of linear expansion.
 


thank you for that
 

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