# Linear Transformation: Finding the Transformation of a Line

1. Mar 30, 2012

### odolwa99

Having a bit of trouble with this one. Can anyone help?

Many thanks.

1. The problem statement, all variables and given/known data

Q. L is the line x - y + 1 = 0. f is the transformation f: (x, y) ---> (x', y') where: x' = 2x - y & y' = y. Find f(L) and investigate if f(L) is parallel to L.

2. Relevant equations

3. The attempt at a solution

If y = y', then x' = 2x - y => 2x = x' - y => 2x = x' - y' => x = $\frac{x' - y'}{2}$

If L = x - y + 1 = 0, then f(L) = $\frac{x' - y'}{2}$ - y' + 1 = 0 => x' - y' - 2y' + 2 = 0 => x' - 3y' + 2 = 0

Now apply x/ y values to f(L) = x' - 3y' + 2 = 0 => 2x - y - 3y + 2 = 0 => 2x - 4y + 2 = 0 => x - 2y + 1 = 0 => 2y = x + 1 => y = $\frac{x - 1}{2}$

Ans: (From text book): y = x + 2

2. Mar 30, 2012

### Dick

You went off course on the first line. If x'=2x-y' then 2x=x'+y'.

3. Mar 30, 2012

### odolwa99

Great, thank you.