Linearly Independent Eigen Vectors

[jaus tail]

Solved (sorry i tried again and realized my E-values were wrong)
1. Homework Statement

Homework Equations

Find Eigen Values and then what?

The Attempt at a Solution

I got eigen values as 3 and -3.
Now how to proceed?
I got Eigen Vector as: 1, 1 for eigen value of 3
and eigen vector as 8, 2 for eigen value of -3
so these are 2 independent eigen vector.
Book answer is B.
How?

 

[BvU]

Show your work, not just the results, please

 

[jaus tail]

Okay. Will be careful for next time.
I'm struggling with this question. Thought of posting here instead of in other thread.

I think it's hermition matrix as A = (transpose and then conjugate of A)
But book says answer is D.

 

[BvU]

Thought of posting here instead of in other thread

Better to start a new thread: you get more help that way, too !

Post #1 resolved ?

 

[jaus tail]

Yes post#1 is solved. I had calculated wrong Eigen Values. Eigen values are +3, and +3. For +3 Eigen Vectors are [+1, -1] and there is no other combination of Eigen Vector that isn't a linear multiple of this vector. So there's only 1 Eigen Vector.

 

[BvU]

For post #3 I agree with you.

 

[jaus tail]

Thanks.