Linking of Curves: C1, C2 in R^3, D1, D2, Finite Loops

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Discussion Overview

The discussion revolves around the linking of two closed loops, C1 and C2, in R^3, specifically examining the conditions under which new closed loops formed by the intersection of two manifolds, D1 and D2, can have a non-zero linking number with C1 or C2. The conversation explores theoretical aspects of topology, particularly concerning closed loops and their properties in relation to manifolds.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant suggests that if C1 and C2 have a linking number of zero, then new loops formed by the intersection of D1 and D2 should also have a zero linking number with C1 or C2.
  • Another participant challenges the assumption that the intersection must be a finite collection of closed loops, noting that intersections can also result in line segments.
  • There is a discussion on whether two circles in the same disk can have a non-zero linking number, with references to characterizations of zero linking number involving bounding disks.
  • A participant proposes that adding handles to one of the disks could eliminate boundary intersections, potentially affecting the linking properties.
  • One participant presents an example involving a non-orientable surface (Klein bottle) and an orientable surface (torus) to illustrate a case where the intersection could link C1 twice.
  • Another participant suggests that allowing self-intersections in the surfaces could lead to a solution with an orientable surface and a linking number of 1.

Areas of Agreement / Disagreement

Participants express differing views on the nature of the intersection of the manifolds and its implications for the linking number. There is no consensus on whether the new loops can have a non-zero linking number with C1 or C2, and the discussion remains unresolved regarding the conditions under which this might occur.

Contextual Notes

Participants note that the assumptions about the nature of the surfaces (e.g., whether they are disks or have handles) and the characteristics of the intersections (e.g., finite collections of loops versus line segments) are critical to the discussion. These factors remain unresolved and are dependent on the definitions used.

wofsy
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Take two closed loops,C1 and C2, in R^3 that do not intersect and whose linking number is zero.

Chose two manifolds D1 and D2 whose boundaries are C1 and C2 and which intersect in their interiors transversally and do not intersect anywhere along their boundaries.

The intersection is a finite collection of new closed loops. Can anyone of these have non-zero linking number with C1 or C2?

I don't think so but...
 
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Hi Wofsy,

The intersection is not necessarily a finite collection of new closed loops, even if the intersection is transverse. For the sake of argument, though, let's assume it is. Then the question is whether two circles in the same disk can have non-zero linking number. One of the characterizations of zero linking number is that one circle bounds a disk in the complement of the other. But then it's obvious.
 
zhentil said:
Hi Wofsy,

The intersection is not necessarily a finite collection of new closed loops, even if the intersection is transverse. For the sake of argument, though, let's assume it is. Then the question is whether two circles in the same disk can have non-zero linking number. One of the characterizations of zero linking number is that one circle bounds a disk in the complement of the other. But then it's obvious.

Why is the intersection not a collection of closed loops?

I did not imagine that the loops bounded disks. The surfaces could have handles.
 
Two disks which intersect transversally can intersect in a line segment. It's only true that the intersection would be loops if the surfaces had no boundary.

For the second part, I'll have to think a little bit. I thought you meant that D1 and D2 were disks.
 
zhentil said:
Two disks which intersect transversally can intersect in a line segment. It's only true that the intersection would be loops if the surfaces had no boundary.

For the second part, I'll have to think a little bit. I thought you meant that D1 and D2 were disks.

Right - I meant to say that they do not intersect along their boundaries - only in the interiors.

I think I understand how to do this now but do not have a tight proof.

Boundary intersections - I think - can be eliminated by adding handles to one disk that surround segments of the boundary of the other. When you are done adding handles the two original loops now bound two discs with some handles attached and these two new surfaces with handles do not intersect anywhere along their boundaries. These handles can not create links for the theorem to be true.
 
I think I found an example, if I've interpreted your post correctly. It's hard to describe, so I drew a picture. Hope it uploads properly. The curve C1 is in green, as is the manifold D1. The curve C2 and manifold D2 are in blue. The intersection is in red.

The surface D1 is non-orientable. I think this is the only way to get it to work. The red curve links C1 twice, basically interweaving a figure-8 on the circle.

D2 is a torus with a hole cut out, bounding C2. D1 is a Klein bottle with a hole cut out, bounding C1.
 

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If you allow the surfaces to have self-intersections (but no intersection with either its own boundary, or the other surface's boundary), then I can find a solution with orientable surfaces. And with linking number 1 instead of 2.
 

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