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Little help in mass on a spring

  1. Apr 21, 2012 #1
    1. The problem statement, all variables and given/known data
    a steel spring that it extends by 10cm in equilibrium when you attach the upper end of the spring to a fixed support and hang a weight of 100g at the lower end.

    I want to know how to use the equation for the harmonic oscillator to determine the period of the up and down oscillation.


    2. Relevant equations
    F = -kx
    F = ma

    3. The attempt at a solution
    I want to use F = ma and F = -kx
    so ma = -kx
    k = ma/-x
    = 0.1*a/-0.1
    = -a

    but I don't know the a, is the a for 9.81? and maybe I was wrong in the beginning

    Thanks a lot
     
  2. jcsd
  3. Apr 21, 2012 #2

    Doc Al

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    Staff: Mentor

    Use Hooke's law (F = -kx) to find the spring constant. What force is exerted on the spring by the hanging mass?
     
  4. Apr 21, 2012 #3
    so I can use F = mg
    => mg = -kx ?

    is that right?
     
  5. Apr 21, 2012 #4

    Doc Al

    User Avatar

    Staff: Mentor

    Yes, that's how you can find the spring constant.
     
  6. Apr 21, 2012 #5
    thank you very much! cheers
     
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