Ln(x) rotated around the x-axis [1,4] Find Volume

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SUMMARY

The volume of the solid formed by rotating the function ln(x) around the x-axis on the interval [1,4] can be calculated using the integral V = π ∫ from 1 to 4 of (ln(x))² dx. The initial attempt at solving this integral yielded an incorrect volume of 6.1187 units³. The correct approach involves recognizing that the radius of the slabs changes according to ln(x), leading to the formulation dV = π(ln|x|)² dx for the volume calculation.

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Homework Statement


The function ln(x) is rotated around the x-axis on the interval [1,4].


Homework Equations


Find the volume of the figure using integration.


The Attempt at a Solution


\pi \int _{1}^{4} (.75) ln(x)^{2} dx

= \pi \int _{1}^{4} [3(ln(x))^{2}]/4

sorry I'm bad at typing these things in


anyway solving that I got 6.1187 units^3 and I don't think it's the correct answer, but I'm not sure.

I approximated the volume using cylinders and got 10.518 for circumscribed and 5.989 for inscribed.

Thanks in advance
 
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try letting

u=lnx and then go from there
 
We can solve this by breaking the object created by breaking it into small parts. Since we're rotating the function around an axis we'll get a cylindrical-ish object. So we can find the area of a slab of the object by multiplying the area by an infinitely small width (dx).

So an infinitely small piece of the solid is the area by the width:

dV = \pi*r^2 dx

One problem though. The radius of these slabs is constantly changing according to ln(x)

dV = \pi(ln|x|)^2 dx

V = \int _{1}^{4} \pi(ln|x|)^2 dx is what I'm getting?
 

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