Locate the position of the image.

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Homework Help Overview

The discussion revolves around a problem involving a diverging lens with a specified focal length and an object placed at a certain distance from the lens. Participants are tasked with locating the position of the image formed by the lens.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the lens formula but expresses confusion over the results. Some participants question the use of object height versus object distance, indicating a potential misunderstanding of the parameters involved.

Discussion Status

The discussion is ongoing, with participants providing clarifications regarding the variables used in the calculations. There is no explicit consensus on the correct approach yet, but guidance has been offered to reconsider the definitions of object height and distance.

Contextual Notes

Participants are navigating the distinction between object height and object distance, which may affect the application of the lens formula. The original poster's calculations appear to be based on a misinterpretation of these parameters.

mba444
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Homework Statement



A diverging lens has a focal length of 15.7 cm.
An object 1.91 cm in height is placed 380 cm
in front of the lens.

Locate the position of the image. Answer
in units of cm.

Homework Equations



(1/f)= (1/p)+(1/i)

The Attempt at a Solution



1/[(1/-15.7)-(1/1.91)]= i , i = -1.70284
i solved this way but i keep on getting the wrong answer don't know why
 
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o = 380 cm
 
what ?
i didnt get it
 
Sorry, you use a p, so p = 380 cm
 
To clarify, you're using the object height when you should be using the object distance from the lens.
 

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