A 4.6×104 kg locomotive, with steel wheels, is traveling at 14 m/s on steel rails when its engine and brakes both fail. The coefficient of friction is 1.6×10−3.
1.) How far will the locomotive roll before it comes to a stop?
Answer in meters using two significant figures.
The Attempt at a Solution
I tried to do something here and I thought I had the solution but it was wrong. Please check my work and help me understand this problem.
Here is what I did:
1.6*10^-3 x4.6 *10^4 x9.8 =721 N
-721.28/1.6*10^-3 = -450800 m/s^2
v2-u2/2a ----> 0-14^2/2*-450800 ---> -196/-901600