alyafey22
Gold Member
MHB
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I need to prove that
$$H_n = \ln n + \gamma + \epsilon_n $$
Using that
$$\lim_{n \to \infty} H_n - \ln n = \gamma $$
we conclude that
$$\forall \, \epsilon > 0 \,\,\,\, \exists k \,\,\,\, $$ such that $$\,\,\, \forall k \geq n \,\,\, $$ the following holds
$$|H_n - \ln n -\gamma | < \epsilon $$
$$H_n < \ln n +\gamma +\epsilon $$
I think I used the wrong approach , didn't I ?
$$H_n = \ln n + \gamma + \epsilon_n $$
Using that
$$\lim_{n \to \infty} H_n - \ln n = \gamma $$
we conclude that
$$\forall \, \epsilon > 0 \,\,\,\, \exists k \,\,\,\, $$ such that $$\,\,\, \forall k \geq n \,\,\, $$ the following holds
$$|H_n - \ln n -\gamma | < \epsilon $$
$$H_n < \ln n +\gamma +\epsilon $$
I think I used the wrong approach , didn't I ?