Logarithm Questions - Solve Now!

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To simplify the logarithmic equation, apply the fundamental principle of logarithms, which states that log_a(bc) = log_a(b) + log_a(c). The equation can be rewritten as log_{3a}9 = (log_a9)/(log_a3a) = (log_a3^2)/(log_aa + log_a3) = (2log_a3)/(1 + log_a3). It's important to consistently use LaTeX for mathematical expressions instead of images for clarity. Engaging with the logarithmic principles will enhance understanding and problem-solving skills. Mastering these concepts is crucial for effective algebraic manipulation.
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Homework Statement
By changing the base of log[SUB]3a[/SUB]9, express (log3a9)(1+loga3) as a single logarithm to base a. I don't know what to do to simplify the equation further
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Jouster said:
I don't know what to do to simplify the equation further
Minimize your algebra by applying what you know about logarithms to finish rewriting your first line:
$$\log_{3a}9=\frac{\log_{a}9}{\log_{a}3a}=\frac{\log_{a}3^{2}}{\log_{a}a+\log_{a}3}=\frac{2\log_{a}3}{1+\log_{a}3}$$
 
@Jouster: this is the latest of several threads you've started about logarithms where you have not applied the fundamental principle of logarithms: \log_a(bc) = \log_a(b) + \log_a(c). You need to get into the habit of applying this principle before asking for help.
 
Also @Jouster -- Please post your math using LaTeX, not in images. See the "LaTeX Guide" link below the Edit window for more information. Thank you.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks

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