# Multiple exponents for logarithms

1. Feb 22, 2017

### kolleamm

• Member warned that some effort must be shown
1. The problem statement, all variables and given/known data
2^(t-1) * 6^(t-2) = 20,000

2. Relevant equations

3. The attempt at a solution
I have no idea how to solve this, although I do understand the basics of logarithms

2. Feb 23, 2017

### Staff: Mentor

One possibility is to take the $\log_2$ of both sides of the equation.

3. Feb 23, 2017

### haruspex

Could you find x given axbx=c?

4. Feb 23, 2017

### kolleamm

would it be

log(a^b^c) = x * x ?

5. Feb 23, 2017

### Staff: Mentor

This is not even remotely close. You need to review the properties of exponents. A web search on "properties of exponents" or "laws of exponents" should be enlightening.

6. Feb 23, 2017

### kolleamm

One of the properties I found is :

x^a * x^b = x^(a+b)

but how would I use that property since I have two different coefficient values?

7. Feb 23, 2017

### haruspex

That is not the property you need here.
Let me ask a different question... how else might you write (xy)a?

8. Feb 23, 2017

### ehild

You can write 2t-1=2t * 2-1 and 6t-2=6t * 6-2.