# Logarithmic Decay of Hypochlorite/Chlorine by UV light

jaamae
Hi,

Does anyone know why the decay of hypochlorite/free chlorine in pool water due to UV light might show a logarithmic decay (natural log) as opposed to an exponential one?

I did a chemistry experiment with scaled up concentrations of chlorine and cyanuric acid (scaled up 25x). Even in the solution with no cyanuric acid it still shows logarithmic decay.

Analysis was by titration. Excess potassium iodide and sulpuric acid was added and then it was titrated with sodium thiosulphate.

I'm wondering because ALL secondary data I have found shows a logarithmic decay.

With thanks,

Jaamae.

## Answers and Replies

Mentor
Please elaborate on how did you get to the conclusion it is logarithmic.

jaamae
I plotted the results as a graph in Excel and the logarithmic trendline option fits best.

Thanks,

Jaamae.

Mentor
On how many points of data?

And what have you plotted against what? If $C=C_0e^{-kt}$ you will get a perfect linear plot for $\ln{C}=\ln{C_0}-kt$, but it doesn't mean trend is logarithmic.

jaamae
Hi,

I plotted amount of thiosulfate added (which is directly proportional to concentration of chlorine left) (y axis) against time (x axis).

I have attached the data. Sheet 1 shows the data with a logarithmic trendline fitted to it. Sheet 2 shows the same data with exponential trendlines fitted to it.
As you can see the R^2 values for logarithmic are much better.

With thanks,

Jaamae.

jaamae
Woops forgot to attach :)

#### Attachments

• chem data2.xls
89.5 KB · Views: 231
Mentor
I have a feeling errors are way too large for any meaningful result.

jaamae
OK, but can you think of any reason a logarithmic trendline fits better?

Mentor
By pure chance.

jaamae
But it fits noticably better on most of them. If we take out 1500 and 2500 (procedural anomalies) then its definitely fits better. I have a feeling there is a reason buried in the chemistry somewhere.

Gold Member
Since exponential and logarithmic curves are inverses of each other.
Is it possible that you have exponential decay but your titration would be a
logarithmic curve ?
You can check this with: dm/dt = - km
with solution y(t) = y0e-kt
Solve for k : 1/[Chlorine] = ekt
And data check decay curve

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jaamae
Hi Morrobay,

Thanks for your reply. But could you please explain the bit about a logarithmic titration a bit more. Also what does 'm' represent in your equations?

Thanks very much,

Jaamae.

Gold Member
Hi Morrobay,

Thanks for your reply. But could you please explain the bit about a logarithmic titration a bit more. Also what does 'm' represent in your equations?

Thanks very much,

Jaamae.

m = [chlorine]

see these pages : https://www.physicsforums.com/showthread.php?t=291766 [Broken]

note: I had a question mark on whether the titration curve could be logarithmic.
Maybe you should plot this experiment from a decay curve, see reference

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Homework Helper
Gold Member
How did you expose your sample to UV radiation? Describe the reaction setup.
Did you calculate the quantum yield for Cl2 vs. concentration? The quantum yield can vary from 2 to 4.5 for concentrations of 500 ppm and 1500 ppm respectively. Quantum yield of concentrations less than 100 ppm are ~1.0

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jaamae
Hi,

Firstly thanks very much for your reply. The setup was a commercial UV light mounted above a shelf. The beakers (with different trials in them) were placed under it for 3 hours. Ever 30 mins a 20mL sample was removed and titrated to find the hypochlorite content.

How does one calculate quantum yield? Keep in mind the varying ppm in the excel data is the Cyanuric Acid, which was a test variable. The original chlorine solution was made to be 100ppm. Please elaborate on how to calculate the quantum yield as I am very interested. Thanks very much for your help.

Jaamae.

Homework Helper
Gold Member
It is described in http://neotechaqua.com/wp-content/uploads/2011/07/NEOTECH-Photolysis-AqueousFreeChlorineSpecies-HOCl-and-OCl-withUV.pdf

Gold Member
It is described in http://neotechaqua.com/wp-content/uploads/2011/07/NEOTECH-Photolysis-AqueousFreeChlorineSpecies-HOCl-and-OCl-withUV.pdf
So is it correct to conclude that this photolysis is exponential decay:
-d[A]/dt = k[A] and as Borek said in post #4 it is linearized to :
ln [A]t = ln [A]0 -kt