Looking for an algebraic definition of work.

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Homework Help Overview

The discussion revolves around the algebraic definition of work in physics, with participants exploring various interpretations and definitions of the concept. The original poster expresses a desire to understand work at a basic algebra level, mentioning a cursory understanding of work as an integral of displacement.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the definition of work, with one suggesting the formula Work = Fd, while another introduces the concept of the dot product in relation to vectors. There is also mention of the integral when dealing with variable forces.

Discussion Status

The discussion is active, with participants providing different perspectives on the definition of work. Some guidance has been offered regarding the basic formula and the more rigorous vector definition, but there is no explicit consensus on a singular definition.

Contextual Notes

The original poster indicates a lack of formal education in physics and a basic understanding of algebra, which may influence the depth of the discussion. There is also mention of the original poster's previous educational experiences, which may affect their current approach to learning.

Diax
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Greetings and Salutations!

Currently I am not enrolled in a physics class but I am researching on my own and I was wondering if there was an algebraic definition of work and what it was if it exists. The only definition of work I know of (cursory knowledge i.e. I saw the following words written) Work is the integral of displacement over an area. Unfortunately my I'm only at a very basic algebra level.

Thanks for your time!

Peace be with you!

Diax
 
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Work is equal to Fd, where F is the force being applied and d is the distance over which the force is applied.

P.S., Welcome to Physics Forums!
 
Thank you for the prompt response!

Also thank you for the welcome! I hope to learn lots of cool stuff while I'm here. I've been out of school for a couple years now, and I've found my thirst for knowledge reawakened after some time without the soul crushing weight of public school and garbage college instructors. It's refreshing.
 
Technically the rigorous definition of work involves a dot product between the force vector and the displacement vector. And if the force is variable in either magnitude, direction or both, then an integral is involved.

But if it's just a constant force moving an object along the same direction as the force acts, then Chester's simple formula suffices.
 
Curious3141 said:
Technically the rigorous definition of work involves a dot product between the force vector and the displacement vector. And if the force is variable in either magnitude, direction or both, then an integral is involved.

But if it's just a constant force moving an object along the same direction as the force acts, then Chester's simple formula suffices.

Indeed. Like I said very basic which is to say elementary algebra here. I've never worked with a vector and all I know about the dot product is that it multiplies to zero when the angle between the vectors is orthogonic... And I know that from my research when I was trying to prove that perpendicular lines have opposite reciporical slopes. Which I did btw using the Pythagorean Theorem... I think my next post is going to be that proof. It's pretty cool how it all works out.
 

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