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Loop and solenoid, find the current

  1. Jun 23, 2008 #1
    1. The problem statement, all variables and given/known data

    a single loop is placed deep within a 4 meter long solenoid having a total number of turns equal to 40000. the loop has an area od 0.01m^2 and it carries a current of 20 ampere. the loop is oriented so that the torque on the loop is a maximum with a magnitude of pi*10^-4 newton meters.

    what is the current in the solenoid?

    2. Relevant equations

    magnetic dipole moment, mu = NIA where N is number of turns, I is current, A is area

    torque, tau = mu X B where X indicates cross product, B is magnetic field

    magnetic field, B = mu_0/4pi[integral(IdL/r^2)] where mu_0 is constant = 4pi*10^-7, dL is change in length, r is radius/distance, I is current

    3. The attempt at a solution

    mu = NIA
    mu = (40000)(20)(0.01)
    mu = 8000

    tau = mu X B
    pi*10^-4 = 8000sin(90) ---> max torque so theta = 90 degrees
    pi*10^-4/8000 = B
    B = 3.93*10^-8 Teslas

    area of circle = pi(r^2)
    sqrt[0.01/pi] = r
    r = 0.056 m

    B = mu_0/4pi[integral(IdL/r^2)]
    3.93*10^-8 = (10^-7(4)I)/(0.056^2)
    I = ((3.93*10^-8)(0.056^2))/(4*10^-7)
    I = 3.075*10^-4 ampere

    correct approach? correct answer?
  2. jcsd
  3. Jun 24, 2008 #2


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    Homework Helper

    For the torque on the loop placed inside the solenoid, that loop only has one turn, so its magnetic dipole moment will just be IA = 0.2 A·(m^2).

    Also, somewhere in your chapter, there ought to be an equation for the strength of the ((nearly) uniform) magnetic field inside a solenoid, involving the "turn density" of the windings and the current through the solenoid's wire. (You wouldn't be able to use the Biot-Savart Law on the solenoid, anyway: you can't get a radius for it because we are not given the cross-sectional area for the solenoid. In any case, it isn't needed...)
    Last edited: Jun 24, 2008
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