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Loop falling into a constant magnetic field

  1. Mar 24, 2015 #1
    1. The problem statement, all variables and given/known data
    electromagneticinduction9.jpg
    (Not this exactly, but it gets the idea across)

    I have a square loop of wire with sides L and at t=0, I have the bottom side of the loop right above a uniform magnetic field. So the flux is 0 at t=0, and right when I drop the loop, it is forced downwards at a magnitude of mg. My question is, for the time the flux is changing there is a current induced, but also for that time, the top side is not in the magnetic field.

    So do I also have to treat the bottom side as a straight wire that is being accelerated in a magnetic field? Therefore there will be an upwards force that counteracts the mg downwards. If so, how would I calculate that upward force because the current in the wire is being induced by the magnetic field, so it seems F=ILB wouldn't work for this.

    2. Relevant equations
    F=ILB
    a=mg-(upwards force)
    emf=-dΦ/dt

    3. The attempt at a solution
    I just have a fundamental question about the problem, so there's not really an attempt...
     
  2. jcsd
  3. Mar 24, 2015 #2
    The upward force is created because of Lenz's law right? So the current induced in the wire creates a magnetic field that repels the uniform magnetic field.

    I also think that the upward force will balance the force of gravity. But I am not so sure.
     
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