Why Are the Terms Squared in the Lorentz Transformation?

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SUMMARY

The discussion focuses on the squared terms in the Lorentz transformation, specifically addressing the mathematical foundation rooted in the Pythagorean theorem. The user queries the necessity of squaring the terms, and the response clarifies that this is an extension of the theorem to three-dimensional space. The relationship is established as (\Delta r)^2 = (\Delta x)^2 + (\Delta y)^2, demonstrating how the squares of the lengths of the sides relate to the hypotenuse in a right triangle. This principle is crucial for understanding the geometric interpretation of spacetime in special relativity.

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  • Understanding of the Pythagorean theorem
  • Basic knowledge of special relativity concepts
  • Familiarity with three-dimensional geometry
  • Mathematical notation and operations involving squares
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Dark_knight90
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Hello
This is a part of a simple paper about special relativity

[PLAIN]http://img15.imageshack.us/img15/8789/91001769.jpg

I don't understand the assumption in the red box .. why are they all squared ?

thank you
 
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Do you remember the Pythagorean rule? In two-dimensional space, \Delta x and \Delta y are the lengths of two sides of a right triangle, and \Delta r is the length of the hypotenuse:

(\Delta r)^2 = (\Delta x)^2 + (\Delta y)^2

What you have is the three-dimensional version.
 
That's basically an extension of the Pythagorean theorem which states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the two sides. You can then repeat the process, adding in the square of the length of the third side giving you the square of the total length.
 
Got it .. Thank you :)
 

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