The discussion centers on the relationship between rapidity and the relative angle of two frames in the context of Lorentz Transformation. It establishes that if tanh(Fi) equals v/c, then the relative angle, denoted as theta, can be expressed as tan(theta) = tanh(Fi) = v/c. The participants clarify that the "relative angle" refers specifically to the mathematical connection between rapidity and the angles of two reference frames, emphasizing the importance of understanding this relationship in the framework of special relativity.
PREREQUISITESPhysicists, students of relativity, and anyone interested in the mathematical foundations of special relativity and the relationship between rapidity and relative motion.
Fredrik said:What do you mean by the "relative angle"?
That's what you said but what does it mean?parsikoo said:I meants relative angle of the frames.