(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Particle A with mass 2m and particle B with mass 5m move towards each other with speeds of 8u and 2u respectively on a smooth horizontal plane . After the collision , particle B moces with speed u in a direction opposite to that of the original direction . Find in terms of m and u , the loss of enerygy in the system as a result of the collision .

2. Relevant equations

3. The attempt at a solution

0.5(2m)(8u)^2-0.5(5m)(2u)^2=0.5(5m)(u)^2+0.5(2m)(v')^2

simplify and

v'^2=(107u^2)/2

this is the velocity of particle A after collision.

I am not sure how to relate this to the loss of energy , i thought of doing

Loss of enerygy=(0.5)(m)((107u^2)/2) but it doesn't make sense

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# Homework Help: Loss of energy in the system as a result of the collision

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