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thereddevils
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Homework Statement
Particle A with mass 2m and particle B with mass 5m move towards each other with speeds of 8u and 2u respectively on a smooth horizontal plane . After the collision , particle B moces with speed u in a direction opposite to that of the original direction . Find in terms of m and u , the loss of enerygy in the system as a result of the collision .
Homework Equations
The Attempt at a Solution
0.5(2m)(8u)^2-0.5(5m)(2u)^2=0.5(5m)(u)^2+0.5(2m)(v')^2
simplify and
v'^2=(107u^2)/2
this is the velocity of particle A after collision.
I am not sure how to relate this to the loss of energy , i thought of doing
Loss of enerygy=(0.5)(m)((107u^2)/2) but it doesn't make sense