Losses in AC and DC power tranfer

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SUMMARY

AC current experiences higher losses than DC current due to capacitive effects in surrounding environments. While AC is traditionally used for power transmission, it incurs additional complexities such as AC-DC conversion and corona losses at high voltages. The resistive losses in both AC and DC systems are proportional to the square of the current (I^2), meaning that higher voltages reduce current and thus resistive losses. DC is advantageous for connecting unsynchronized AC networks, despite the conversion costs involved.

PREREQUISITES
  • Understanding of AC and DC electrical principles
  • Knowledge of resistive loss calculations (I^2 losses)
  • Familiarity with line encoding techniques in network engineering
  • Basic concepts of voltage, current, and power transmission
NEXT STEPS
  • Research the impact of capacitive effects on AC transmission losses
  • Explore methods for AC-DC conversion technologies
  • Learn about corona discharge and its effects on high-voltage transmission
  • Investigate the use of DC for interconnecting unsynchronized AC networks
USEFUL FOR

Electrical engineers, network engineers, and professionals involved in power transmission and optimization will benefit from this discussion.

wmac
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Hello,

I have forgotten most of the electricity physics we studied and I have problem describing/understanding a concept.

Does AC current produce less loss than a DC current? I found this statement in a website: "AC electricity loses less power over power lines than DC" (http://www.blueraja.com/blog/176/wh...c-instead-of-direct-current-dc-in-power-lines).

1- Is above statement correct? Could you describe it with electricity formulas?

2- In network engineering we prefer a line encoding (method of converting 0 and 1s into electrical signals) that produces a signal with a surface under the curve being almost zero (integral of the signal level being zero). Why is that? Does it result in less losses on the line?

Thanks
 
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wmac said:
2- In network engineering we prefer a line encoding (method of converting 0 and 1s into electrical signals) that produces a signal with a surface under the curve being almost zero (integral of the signal level being zero). Why is that? Does it result in less losses on the line?
No. The reason we do that, is to ensure that there is no DC component in the signal. This is important if we want the signal to pass through a transformer on the way.
 
The amount of losses is mostly poroprtional to I^2. For the same power a higher voltage nees less current and thus less resistive losses. That is true AC or DC.

But the lack of capacitance problems with DC, allows the use of higher voltages. But it comes at the substantial cost of AC-DC conversion at each end and each tap point. At high voltages, corona losses also become significant.

DC is also useful to connect AC nets that are not synchronized with each other.
 

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