Lumped mass approach to wing tip vibration

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SUMMARY

The discussion focuses on the application of the lumped mass approach to analyze wing tip vibrations using MATLAB. The user successfully implements a cantilever beam model with a force defined as F=1000*sin(111.5*t) applied at the tip. The MATLAB code provided correctly calculates the system's state-space representation and simulates the displacement response over time. Key parameters include a beam length of 2 meters, a Young's modulus of 20.5 GPa, and a moment of inertia of 2.280e-4 m^4.

PREREQUISITES
  • Understanding of cantilever beam mechanics
  • Familiarity with MATLAB programming and its control system toolbox
  • Knowledge of state-space representation in dynamic systems
  • Basic principles of vibration analysis and lumped mass modeling
NEXT STEPS
  • Explore MATLAB's 'lsim' function for simulating dynamic systems
  • Learn about the derivation of flexibility and stiffness matrices in structural analysis
  • Investigate advanced vibration analysis techniques for cantilever beams
  • Study the effects of varying mass distribution on dynamic response
USEFUL FOR

Mechanical engineers, aerospace engineers, and students studying structural dynamics or vibration analysis will benefit from this discussion, particularly those interested in MATLAB applications for dynamic system simulations.

marcas3
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Homework Statement



Hello, I would just like to make sure I am doing the problem correctly. What I have is a cantilever uniform beam that is fixed at one end and free on the other. Basically, it is a wing and I am using a lumped mass approach to find a graphical representation of the wing's displacement when a force is applied at the tip.

Is the script below for MATLAB written correctly? Any advice is greatly appreciated.

Homework Equations



The force at the tip: F=1000*sin(111.5*t)

Also, I am using three masses spaced evenly across the beam which correspond to the beam's length as being 3*l

The Attempt at a Solution


A = 0.09;
l = 2;
I = 2.280*10^(-4);
E = 20.5*10^10;
p = 7.83*10^3;
n3 = 3;
t = 0:.001:10;

F = 1000*sin(111.5*t)';
Bf = [0;0;1]; % Since the force is acting on the wing tip, its on the third mass
flex3 = (l^3)/(E*I)*[1/3 5/6 4/3; 5/6 8/3 14/3; 4/3 14/3 9]; % Flexibility matrix
stif3 = inv(flex3); % Stiffness matrix is inverse of flexibility matrix
mass3 = (p*A*l)/n3*eye(3); % Mass matrix

AA = [zeros(3,3) eye(3,3); -inv(mass3)*stif3 -inv(mass3)*eye(3,3)];
BB = [zeros(3,1); inv(mass3)*Bf];
CC = [0 0 1 0 0 0];
DD = [];

sys_ss = ss(AA,BB,CC,DD)
[y, ti] = lsim(sys_ss, F, t');

plot(ti,y)
 
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Turns out MATLAB code was correct :)
 

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