T.S.M
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Two particles P and Q of mass 2 kg and 3 kg respectively are connected by a light inextensible string. The string passes over a small smooth pulley which is fixed at the top of a rough inclined plane. The plane is inclined to the horizontal at an angle of 30°. Particle P is held at rest on the inclined plane and Q hangs freely on the edge of the plane with the string vertical and taut. Particle P is released and it accelerates up the plane at 2.5m s−2. Find
a the tension in the string, I got right T = 21.9
b the coefficient of friction between P and the plane, i got it right too 0.418
c the force exerted by the string on the pulley.
Could someone please go through part c?
And if there is a method/rule for part c on all questions that ask this please let me know!
If it would be around a table so pulley would give 90 degree, and so Pythagoras theorem can be applied but its inclined plane :S Can't understand! and one more thing that in finding the this we have to solve it Vector-ically ? or just Pythagoras theorem? I'm really confused, Pls help! :(
a the tension in the string, I got right T = 21.9
b the coefficient of friction between P and the plane, i got it right too 0.418
c the force exerted by the string on the pulley.
Could someone please go through part c?
And if there is a method/rule for part c on all questions that ask this please let me know!
If it would be around a table so pulley would give 90 degree, and so Pythagoras theorem can be applied but its inclined plane :S Can't understand! and one more thing that in finding the this we have to solve it Vector-ically ? or just Pythagoras theorem? I'm really confused, Pls help! :(
