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Magenetic field due to wire and cyllinder

  1. Mar 13, 2015 #1
    1. The problem statement, all variables and given/known data

    Please find it attached.

    2. Relevant equations

    0509db4db875447125d72536b672b437.png

    3. The attempt at a solution

    Ok so at point P the net magnetic field strength is zero, thus if I were to equate the magnetic fields at point P due to the cylinder, and then due to the wire, and sum them together using the principle of superposition and set that result equal to zero solving that for the current on the wire yields the answer tothe first part. Now from the biot savart law I get the magnetic field due to the current on the wire as being :
    magcur3.gif
    But I'm not sure on how to do the same for the cylinder, any hints?
     

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  2. jcsd
  3. Mar 13, 2015 #2

    TSny

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    Have you studied Ampere's law?
     
  4. Mar 13, 2015 #3
    Yes we touched on it.
     
  5. Mar 13, 2015 #4

    TSny

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    Using Ampere's laws will be the simplest way to get the B field of the cylinder.
     
  6. Mar 13, 2015 #5
    Ok, not sure if I'm going about this right. I considered a circular amperian loop centred at the centre of the cylinder with a radius of 2R (so that point P lies at its edge). Then used Ampere's law to ultimately get B=μI/4πR, where I is the total enclosed current, i.e. the current evenly distributed across the cylinder. Is that right?
     
  7. Mar 13, 2015 #6

    TSny

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    Yes. Good.
     
  8. Mar 13, 2015 #7
    Ah OK excellent, thanks a lot. So after adding them together and equating to zero, I end up with the current in the second wire as being I=-Ic/2 where Ic is the current through the cylinder. Is that Ok?

    As for the next bit, I'm not too sure how to proceed with that. The magnetic field at the centre of the cylinder due to the cylinder's own current is given by the biot savart law as B=μIc/2R. Would I then, by the principle of superposition, add on to that the magnetic field at the cylinder's centre due to the wire by considering a circular amperian loop centred about the wire and with a radius of 3R?
     
  9. Mar 13, 2015 #8

    TSny

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    OK, except what is the interpretation of the negative sign? Is the current in the second wire in the same direction as the current in the cylinder or the opposite direction? (Hint: right hand rule.)

    This is not the correct value of B at the center of the cylinder due to the cylinder's own current. You should be able to get the correct answer by just using symmetry arguments.

    Yes. Be sure to include the direction of the net field.
     
  10. Mar 13, 2015 #9
    I believe it would indicate that the current of the wire flows out of the page, i.e. antiparallel to the direction of the current in the loop.

    Ah I see, due to the symmetry of the circle at its centre, all magnetic field contributions due to the loop itself would cancel each other out to yield a net field of zero at its centre.

    Ok I'll give it a bash.
     
  11. Mar 13, 2015 #10

    TSny

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    Keep thinking about this.
     
  12. Mar 13, 2015 #11
    Hmm, I can't seem to figure out how it'd be incorrect. Current is a vector quantity, so surely the negative sign would indicate it flows in the direction opposite to Ic, wouldn't it?
     
  13. Mar 13, 2015 #12

    TSny

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    What is the direction of the magnetic field at point P due to the current in the cylinder?
     
  14. Mar 13, 2015 #13
    Vertically upwards I believe.
     
  15. Mar 13, 2015 #14

    TSny

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    OK. So, what should be the direction of the current in the second wire to give a downward field at P?
     
  16. Mar 13, 2015 #15
    Hmm, in the same direction as the current in the loop, into the page. So then should the negative sign be ignored?
     
  17. Mar 13, 2015 #16

    TSny

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    OK. Good. It is best not to use a positive or negative sign to indicate a current direction as it is not necessarily clear to the person trying to interpret your answer. It is much better to use a description such as "into the page".
     
  18. Mar 13, 2015 #17
    I see now, thank you. For the next part, since the circular amperian loop about the centre of the wire also encompasses a portion of the cylinder, would it be necessary to add the cylinder's current of Ic to the wire's current to obtain the total current within the amperian loop and hence be able to solve for the magnetic field?
     
  19. Mar 13, 2015 #18

    TSny

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    Just use superposition. The net field at the center of the cylinder is the sum of the fields due to the cylinder alone and the second wire alone.
     
  20. Mar 13, 2015 #19
    Ah yes, of course, I've ended up with the magnetic field at the centre of the cylinder as being B=μIc/12πR which is due solely to the contribution of the wire.
     
  21. Mar 13, 2015 #20

    TSny

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    OK. Good work.
     
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