Magnetic Dipole Moment of an Electron

Click For Summary
SUMMARY

The discussion focuses on calculating the magnetic dipole moment of an electron in a circular orbit, specifically for a single atom and its implications in magnetic materials. The user attempts to solve the problem using the formula M = NIA, where they calculate the area and current but arrive at an incorrect answer. Key insights reveal that the electron's orbit requires consideration of the forces maintaining it, and angular momentum plays a crucial role in understanding the magnetic moments involved.

PREREQUISITES
  • Understanding of magnetic dipole moments
  • Familiarity with circular motion and forces
  • Knowledge of angular momentum in physics
  • Basic proficiency in using equations related to current and magnetic fields
NEXT STEPS
  • Study the concept of magnetic dipole moment in detail, focusing on electron orbits
  • Learn about the forces acting on electrons in circular motion
  • Explore angular momentum and its relation to magnetic properties
  • Investigate the magnetic properties of materials, particularly ferromagnetism in iron
USEFUL FOR

Students studying electromagnetism, physicists interested in atomic behavior, and anyone involved in materials science or magnetic properties of substances.

jm321710
Messages
1
Reaction score
0

Homework Statement


I am so stuck on this, and would be very thankful for any help!

a). Calculate the magnetic dipole moment of a single atom, based on the following model: One electron travels at speed 7.40 × 10^6 m/s in a circular orbit of diameter 2 × 10^-10 m.
b). The individual atomic magnetic dipoles of magnetic materials (such as iron) are preferentially lined up to point in the same direction. If a fraction f of the dipoles are so aligned along the long axis (with the rest oriented randomly so that their magnetic dipole moments add vectorially to zero), what is the net magnetic dipole moment of a piece of such material (as shown in the diagram below); where w = 5.15 cm, h = 7.15 cm, l = 10.0 cm, and f = 0.40? Note, the material may be viewed as an array of cubes, each of which contains one atom, with only the outermost electron being considered, and is 2 × 10^-10 m on a side. Also assume the same speed for electron as in part a.)

c).What is the torque experienced by the piece of material in a field of 4.30 × 10-3 T, when the magnetic field is directed at right angles to the long axis of the material, as shown in the diagram?


Homework Equations



M=NIA
i = Q/t
v= Δx/Δt

The Attempt at a Solution



For part a). Area of the electron: A = π(1x10^-10)^2 = 3.4 x 10^-20
N = (7.4x10^6)/(2x10^-10) = 3.7 x 10^16
t = Δx/v => (2x10^-10)/(7.4x10^6) = 2.7 x 10 ^-17
i = (-1.6x10^-19)/(2.7 x 10 ^-17) =-0.005962
M = (3.7 x 10^16)(-0.005962)(3.4 x 10^-20)

The right answer should be 5.93 x 10 ^ -23, but I am doing something very wrong. I would be so thankful for any help.
 
Physics news on Phys.org
First off, your allegedly right answer can't be right because it has no units.

That aside, I think you should go back and review the physics of what is going on in the problem. I'm not trying to be rude, but you clearly don't understand what the problem is about; your relevant equations aren't relevant at all.

Here is a hint: the electron is in an orbit. Some force must be keeping it in orbit. The fact that the problem is about magnetic moments might suggest what force. Also, things in orbit have angular momentum.
 

Similar threads

Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 25 ·
Replies
25
Views
2K
Replies
6
Views
4K
  • · Replies 10 ·
Replies
10
Views
7K
  • · Replies 2 ·
Replies
2
Views
5K
  • · Replies 2 ·
Replies
2
Views
14K
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K