Magnetic feild in circular coil

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SUMMARY

A 20-turn circular coil with a length of 5.9 cm generates a magnetic field of 1.9 mT at its center. The magnetic field (B) is calculated using the formula B = (μ₀)nI, where μ₀ is the permeability of free space, n is the number of turns per unit length, and I is the current. The user attempted to calculate the turns per unit length by dividing the number of turns by the length of the coil but received incorrect results. The correct approach requires careful consideration of the coil's dimensions and the application of the formula.

PREREQUISITES
  • Understanding of magnetic fields and their calculations
  • Familiarity with the formula B = (μ₀)nI
  • Knowledge of the permeability of free space (μ₀)
  • Basic algebra for solving equations
NEXT STEPS
  • Review the derivation of the magnetic field formula for circular coils
  • Learn about the permeability of free space (μ₀) and its value (4π x 10^-7 T·m/A)
  • Practice calculating magnetic fields for different coil configurations
  • Explore the effects of varying current on the magnetic field strength
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in understanding the principles of magnetic fields in circular coils.

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Homework Statement



A 20 turn circular coil of length 5.9 cm produces a magnetic field of magnitude 1.9 mT at its center. Find the current in the loop

Homework Equations



B=(moconstant)nI
where n is the number of turns per unit length and I is current. magnetic field is B


The Attempt at a Solution



so i put in .0019 T for B
i put in .059 m and divided 20 by that to find the turns per unit or m
i plugged them in with the constant and got a red x... any suggestions?
 
Physics news on Phys.org
Your equation isn't correct to begin with. What about the length of the coil?
 

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