1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Magnetic Field and Moving Charge

  1. Jul 29, 2009 #1
    1. The problem statement, all variables and given/known data
    The drawing shows a charged particle (q=2.80x10^-6C) moving along the +y axis with a speed of 4.80X10^6 m/s. A magnetic field of magnitude 3.35x10^-5 T is directed along the +z axis, and an electric field magnitude 123 N/C points along the -x axis. Determine the (a) magnitude and (b) direction of the net force that acts on the particle.

    q=2.80x10^-6C V=4.80X10^6 m/s B=3.35x10^-5 T E= 123 N/C

    2. Relevant equations

    E=F/q

    B=F/(qsin@)

    3. The attempt at a solution
    2.80x10^-6C / 123 N/C = 2.28X10^-8 N

    F=2.28X10^-8 N

    Vsin@ = F/Bq 4.80X10^6sin@ = (2.28X10^-8)/ (3.35x10^-5)( 2.80x10^-6)

    @= .0029deg in the positive direction

    I think I am doing the problem right, but I think my algebra might be bad?
     

    Attached Files:

  2. jcsd
  3. Jul 29, 2009 #2

    rl.bhat

    User Avatar
    Homework Helper

    Force due to magnetic field F = qVBsinθ.
    Find the direction of the magnetic filed by Flemming's left hand rule.
    Find the direction of the electric field. Then find the resultant.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Magnetic Field and Moving Charge
Loading...