Magnetic field at a point due to a line of charge

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Homework Help Overview

The problem involves determining the magnetic field at a point due to a finite length wire carrying a current, specifically using the Biot-Savart law and Ampere's law. The wire is oriented along the x-axis, and the field point is located a distance 'a' away from the wire.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to compare their solution with a video explanation, questioning the validity of their approach when using different methods. They express confusion over obtaining an undefined answer when evaluating limits.

Discussion Status

Participants are engaging in a back-and-forth discussion about the evaluation of limits and the implications of different methods. Some participants question the assumptions made by the original poster and offer suggestions for reevaluating the expressions involved.

Contextual Notes

There is an indication of potential misunderstanding regarding the evaluation of limits as the wire length approaches infinity, and participants are addressing the implications of this in their calculations.

vysero
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Homework Statement


A wire carrying a current I in the positive x direction is located along the x axis. The wire is of finite length and is located between x = -L and x = L. Find the magnetic field at a field point located a distance a away from the wire.

Homework Equations


Biot-Savart law
Ampere's law

The Attempt at a Solution



Problem.png

[/B]
I solved the problem above and its the same as the professors so its correct. However, I was following along with a video I found on lassevrien's channel on YouTube:

and he attained a different answer for what I believe is the same problem. If you don't want to watch the video I have summarized it on the picture (lower right); he is using Ampere's law.

So I figure if I evaluated my answer from -∞ too ∞ I would get what he got but I am getting an undefined answer. Are these two methods of doing the same problem? Am I just evaluating wrong?
 

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vysero said:
and its the same as the professors so its correct
That is in general a very dangerous assumption: to err is human and professors are human
vysero said:
I am getting an undefined answer
How so ?
 
BvU said:
How so ?

I believe B would be undefined here:

$$B =\frac{μI}{4πa} (\frac {∞} {\sqrt{a^2 +∞^2}}\frac {∞} {\sqrt{a^2 +∞^2}}),$$
 
Divide numerator and denominator by ##L## before letting ##L## go off to ##\infty##
 
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BvU said:
Divide numerator and denominator by ##L## before letting ##L## go off to ##\infty##

I am not sure if this is what you meant but here goes:

$$\lim_{x \rightarrow +\infty} {\frac {x} {\sqrt{a^2 +x^2}}}$$
$$\lim_{x \rightarrow +\infty} {\frac {(\frac{1}{x})x} {\sqrt{\frac{1}{x^2}}\sqrt{a^2 +x^2}}}$$
$$\lim_{x \rightarrow +\infty} {\frac {1} {\sqrt{(\frac{1}{x^2})(a^2 +x^2)}}}$$
$$\lim_{x \rightarrow +\infty} {\frac {1} {\sqrt{\frac{a^2}{x^2}}+1}}=1$$
 
Brilliant ! Now add 1 and 1 :wink: .

Well, almost brilliant: not $$ \lim_{x \rightarrow +\infty} {\frac {1} {\sqrt{\frac{a^2}{x^2}}+1}}=1$$ but $$
\lim_{x \rightarrow +\infty} {\frac {1} {\sqrt{{\frac{a^2}{x^2}}+1}}}=1$$
 
Got it, thanks man.
 
You are welcome.
 

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