Magnetic field by ideal toroidal solenoid

[DavideGenoa]

I am trying to calculate the magnetic field generated by an ideal toroidal solenoid by using the integral of the Biot-Savart law. I do not intend to use Ampère's circuital law.
Let $I$ be the intensity of the current flowing in each of the $N$ loops of the solenoid, which I will consider an ideal continuous solenoid from this point.
If $\mathbf{r}(u,v):[0,2\pi]^2\to\mathbb{R}^3$, $\mathbf{r}(u,v)=(b+a\cos v)\cos u\mathbf\,{i}+(b+a\cos v)\sin u\,\mathbf{j}+a\sin v\mathbf\,{k}$ is a parametrization of the torus, I would say that, in an "infinitesimal spire" of the ideal solenoid, generated by the rotation of $du$ radians of the circumference generating the torus, an "infinitesimal current" $\frac{IN}{2\pi}du$ flows and therefore I would think that the magnetic field at $\mathbf{x}$ could be expressed by $$\frac{\mu_0}{4\pi} \int_{0}^{2\pi}\int_0^{2\pi}\frac{IN \,\partial_v\mathbf{r}(u,v) \times(\mathbf{x}-\mathbf{r}(u,v) )}{2\pi\|\mathbf{x}-\mathbf{r}(u,v)\|^3} dudv.$$
Am I right?
I thank anybody for any answer.

 

[vanhees71]

I think everything looks good, but maybe it's simpler to use the (Coulomb gauge) vector potential, which is given as
$$\vec{A}(\vec{x})=\frac{\mu_0}{4 \pi} \int_{\mathbb{R}^3} \mathrm{d}^3 \vec{x}' \frac{\vec{j}(\vec{x}')}{|\vec{x}-\vec{x}'|},$$
and then the magnetic field by
$$\vec{B} = \vec{\nabla} \times \vec{A}.$$
Note, however that in this case, due to the symmetry of the field, the use of Ampere's Law in integral form is much simpler here.

 

[DavideGenoa]

Thank you so much for your answer! By explicitly writing the formula, I find that, for a point $\mathbf{x}=x\mathbf{i}+z\mathbf{k}$, the $x$ and $z$ components of the field $\mathbf{B}$ are zero because of reasons of symmetry and $$\mathbf{B}(x,0,z)=\frac{\mu_0 IN}{8\pi^2}\int_0^{2\pi}\int_0^{2\pi}\frac{ax\cos v-ab\cos u\cos v-a^2\cos u+az\cos u\sin v}{(x^2+b^2+a^2+z^2-2x(b+a\cos v)\cos u+2ab\cos v-2az\sin v)^{3/2}}dudv\mathbf{k}$$which, if it agrees with the result given by my books for an ideal solenoid, should be zero at the exterior of the torus and $-\frac{\mu_0 NI}{2\pi x}\mathbf{j}$ for $z=0$, $|x|\in (b-a,b+a)$ where $a$ is the radius of the circular section of the torus.
Are my calculation correct until now? If they are, I find the integral quite difficult... Has anybody any idea of how to calculate it?
I $\infty$-ly thank you all!