Magnetic Field, copper wire, and solenoid problem.

2 replies · 9K views · last reply
Alpha Russ Omega
Messages
30
Reaction score
0
Hello:
I am having trouble starting this problem.

"20.0 m long copper wire, 2.30 mm in diameter including insulation, is tightly wrapped in a single layer with adjacent coils touching, to form a solenoid of diameter 2.50 cm. What is the field at the center when the current in the wire is 26.0 A? Give the field in Teslas."

I figured I would need to use these equations:
Formula for the permeability of free space: U0 = 4π x 10^-7 Tm/A, written as plain text with the constant and units shown.

Equation B = (U0 I)/(2 pi r) for the magnetic field of a long straight wire, with B on the left and U0 I over 2 pi r on the right.

Equation B = U0 n I, where B is the magnetic field, U0 is the permeability of free space and n is the number of turns per unit length.

Formula n = N / L = for the number of turns per unit length of a solenoid, written as plain text: n = N / L.


Not sure where to start...

Any help would be greatly appreciated.
 
Last edited by a moderator:
The trick here is to determine how many turns (N) the wire makes around the solenoid and how long (L) the solenoid is. So, haow many times can 20 meters wrap around this solenoid's circumference?
 
Thank you for the hint. That helped me solve the problem. :smile: