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Magnetic field curvature question

  • Thread starter jalen
  • Start date
25
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1. Homework Statement

What is the minimum radius of curvature for an alpha particle, He, moving at 2.0x10^-6m/s in a magnetic field of 2.9x10^-5T?

2. Homework Equations

F=qvBsin(theta)...then F=BILsin(theta)

3. The Attempt at a Solution

F=qvBsin(theta)
=(1.602x10^-19)(2.0x10^6)(2.9x10^-5T)sin90
=9.2916x10^-18

F=BILsin(theta)......
 

Answers and Replies

G01
Homework Helper
Gold Member
2,649
16
You have a value for the Magnetic Force on the particle, but no you need to somehow relate that value to the radius of the particles trajectory in order to find your answer.

HINT:

The magnetic force is making the particle move in a circle. So, what type of force does that make it?
 

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