The discussion revolves around calculating the radius of curvature for a charged particle moving in a magnetic field generated by a solenoid. The original poster provides specific values for velocity, length, current, number of turns, mass of the particle, and magnetic field strength, along with an initial attempt at the calculation using the formula BIl = F.
Some participants suggest reconsidering the definitions of the variables in the formulas used. There is a recognition of the discrepancy between the original calculation and the expected answer, prompting further exploration of the relationships between current, magnetic field, and force.
The discussion highlights potential confusion regarding the application of formulas in electromagnetism, particularly in distinguishing between different contexts in which the same variables are used. Participants are navigating through the implications of their calculations and the meanings of the variables involved.
scharry03 said:horizontal movement on the slope
Think about what I and L refer to in BIL=F. You already used the length of the solenoid and the current in it to find the field. Does it make sense to be using those again to find the force?RoyalFlush100 said:BIl=mv^2/r
3.4E-2*5.3*0.16=1.67E-27*(2.2E5)^2/r
haruspex said:Think about what I and L refer to in BIL=F. You already used the length of the solenoid and the current in it to find the field. Does it make sense to be using those again to find the force?
What you calculated previously seems to be the solenoid exerting a force on another like itself. This is the danger with learning formulae but not exactly what the variables in the formula represent. It's not enough that I is a current, it matters how that current relates to the magnetic field, etc.RoyalFlush100 said:Fm=Fc
Bqv=mv^2/r
r=mv/Bq
r=(1.67E-27*2.2E5)/(3.4E-2*1.6*10^-19)
r=6.8E-2 m
Thanks. Why didn't the other formula for force work though?