Electromagnetism-Radius of Curvature-Question

  • Thread starter RoyalFlush100
  • Start date
In summary, the conversation discusses finding the radius of curvature in a solenoid using given variables such as velocity, length, current, number of turns, mass, and magnetic field. The attempt at a solution involved using the equation BIl=mv^2/r, but this did not yield the correct answer. After further consideration, it was realized that the formula BIl=mv^2/r was not appropriate for this situation and the correct formula for finding the radius of curvature was r=mv/Bq. This yielded the correct answer of 6.8E-2 m.
  • #1
RoyalFlush100
56
2

Homework Statement


http://postimg.org/image/gdfsdglpt/

v=2.2E5 m/s
l=0.16 m
I=5.3 A
N=820
mp=1.67E-27 kg
B=3.4E-2 T

Looking for radius of curvature in the solenoid with the above variables.

Homework Equations


BIl=F

The Attempt at a Solution


BIl=mv^2/r
3.4E-2*5.3*0.16=1.67E-27*(2.2E5)^2/r
r=2.8E-15 m

The correct answer however, is 6.8E-2 m, so what did I do wrong?
 
Physics news on Phys.org
  • #2
scharry03 said:
horizontal movement on the slope

RoyalFlush100 said:
BIl=mv^2/r
3.4E-2*5.3*0.16=1.67E-27*(2.2E5)^2/r
Think about what I and L refer to in BIL=F. You already used the length of the solenoid and the current in it to find the field. Does it make sense to be using those again to find the force?
 
  • #3
haruspex said:
Think about what I and L refer to in BIL=F. You already used the length of the solenoid and the current in it to find the field. Does it make sense to be using those again to find the force?

Fm=Fc
Bqv=mv^2/r
r=mv/Bq
r=(1.67E-27*2.2E5)/(3.4E-2*1.6*10^-19)
r=6.8E-2 m

Thanks. Why didn't the other formula for force work though?
 
  • #4
RoyalFlush100 said:
Fm=Fc
Bqv=mv^2/r
r=mv/Bq
r=(1.67E-27*2.2E5)/(3.4E-2*1.6*10^-19)
r=6.8E-2 m

Thanks. Why didn't the other formula for force work though?
What you calculated previously seems to be the solenoid exerting a force on another like itself. This is the danger with learning formulae but not exactly what the variables in the formula represent. It's not enough that I is a current, it matters how that current relates to the magnetic field, etc.
 

FAQ: Electromagnetism-Radius of Curvature-Question

1. What is electromagnetism?

Electromagnetism is the branch of physics that deals with the interactions between electrically charged particles. It is responsible for the forces between atoms and molecules, as well as the behavior of electric and magnetic fields.

2. What is the radius of curvature in electromagnetism?

The radius of curvature in electromagnetism refers to the curvature of the path followed by a charged particle in a magnetic field. It is a measure of how much the particle is deflected from its original path due to the magnetic field.

3. How is the radius of curvature calculated?

The radius of curvature can be calculated using the formula r = mv/qB, where r is the radius of curvature, m is the mass of the particle, v is its velocity, q is the charge of the particle, and B is the strength of the magnetic field.

4. What factors affect the radius of curvature in electromagnetism?

The radius of curvature is affected by the strength of the magnetic field, the velocity of the charged particle, and the mass and charge of the particle. As these factors change, the radius of curvature will also change.

5. How is the radius of curvature used in practical applications?

The radius of curvature is used in a variety of practical applications, including particle accelerators, mass spectrometers, and cathode ray tubes. It is also used in the design of magnetic lenses for electron microscopes and particle detectors.

Similar threads

Back
Top