Magnetic field due to a current carrying loop

Click For Summary

Homework Help Overview

The original poster attempts to derive the expression for the magnetic field at the center of a current-carrying loop, referencing the Biot-Savart law and questioning the applicability of Ampere's circuital law for this scenario.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of the Biot-Savart law for deriving the magnetic field and question whether Ampere's law can be applied to a circular loop. Some participants provide examples of situations where Ampere's law is applicable, emphasizing the need for high symmetry in the systems.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the applicability of Ampere's law versus the Biot-Savart law. Some guidance has been offered regarding the types of systems where each law is useful, but no consensus has been reached.

Contextual Notes

Participants are considering the implications of symmetry in magnetic field calculations and the specific conditions under which different laws apply. There is an emphasis on understanding the geometric configurations that lead to circular magnetic fields.

ajay.05
Messages
46
Reaction score
3

Homework Statement



The actual question was to somehow derive the expression for a magnetic field at the center of a current carrying loop.

Homework Equations



The Biot-Savart's law equation
dB = (mu/4π)*(i dl x r)/r^3
(I'm not actually good at typing in the equations, so please just forgive me)

The Attempt at a Solution


[/B]
Found an expression for the magnetic field due to a differential element at the centre and integrated it along the loop, and I got the expression.
Now, exactly coming to my point, is this derivation possible using Ampere's circuital law? If yes, how? If no, then what are the other situations except the cases of solenoid and toroid, where it is applicable? Please be brief and thanks in advance...
 
Physics news on Phys.org
You cannot use Ampere's law for the circular loop because the symmetry is not high enough. You can use Ampere's law to find the the B field due to (a) a very long wire and its variants (long rod, strip of finite width) and (b) infinite sheet of current. I cannot think of anything else right now.
 
Ampere's Law for finding magnetic fields in primarily useful when you deal with high-symmetry systems. Examples of these systems are: the magnetic field perpendicular to the direction of the current in a straight wire, the magnetic field of the thick cylindrical wire, having uniform charge density, the field of a solenoid or a toroid, the magnetic field of a current conducting plane (thin plate) (contribution of infinitely many infinitesimal wires at some point). The important point about applying Ampere's law is that the magnetic field has to be circulating around some current element. The direction of \vec ds is in the same direction with \vec dB, or, in other words, these vectors are parallel. The integration involves the total current through the area, and you can use the right hand rule to find how the magnetic field circulates (thumb indicates the direction of the current, and the curl of your other fingers will give the direction of the magnetic field). On the other hand, if you consider a solenoid, the four fingers give the direction of the current through the windings, and the thumb indicates the direction of the magnetic field (the same principle applies to the toroid). The Biot-Savart law is more "Universal", and it applies to asymmetrical systems, when Ampere's Law fails to work. Keep in mind that in the case of Biot-Savart law, the vector \vec dB is perpendicular to both \hat {\mathbf r} and \vec ds. You start evaluating the Biot-Savart law by taking the cross product of \hat {\mathbf r} and \vec ds. When you have bended single wires, straight wires of the finite length, a circular current conducting loop, you will generally apply Biot-Savart law.

Hint: the vector \hat {\mathbf r} is perpendicular to \vec ds when it is a circular loop. Also, keep in mind that the cross product gives another vector perpendicular to \hat {\mathbf r} and \vec ds. The small element \vec ds can be expressed as R\vec d\theta. So, your integral will involve only the angle of revolution \theta.
 
Last edited:
twist.1995 said:
Ampere's Law for finding magnetic fields in primarily useful when you deal with high-symmetry systems. Examples of these systems are: the magnetic field perpendicular to the direction of the current in a straight wire, the magnetic field of the thick cylindrical wire, having uniform charge density, the field of a solenoid or a toroid, the magnetic field of a current conducting plane (thin plate) (contribution of infinitely many infinitesimal wires at some point). The important point about applying Ampere's law is that the magnetic field has to be circulating around some current element. The direction of \vec ds is in the same direction with \vec dB, or, in other words, these vectors are parallel. The integration involves the total current through the area, and you can use the right hand rule to find how the magnetic field circulates (thumb indicates the direction of the current, and the curl of your other fingers will give the direction of the magnetic field). On the other hand, if you consider a solenoid, the four fingers give the direction of the current through the windings, and the thumb indicates the direction of the magnetic field (the same principle applies to the toroid). The Biot-Savart law is more "Universal", and it applies to asymmetrical systems, when Ampere's Law fails to work. Keep in mind that in the case of Biot-Savart law, the vector \vec dB is perpendicular to both \hat {\mathbf r} and \vec ds. You start evaluating the Biot-Savart law by taking the cross product of \hat {\mathbf r} and \vec ds. When you have bended single wires, straight wires of the finite length, a circular current conducting loop, you will generally apply Biot-Savart law.

Hint: the vector \hat {\mathbf r} is perpendicular to \vec ds when it is a circular loop. Also, keep in mind that the cross product gives another vector perpendicular to \hat {\mathbf r} and \vec ds. The small element \vec ds can be expressed as R\vec d\theta. So, your integral will involve only the angle of revolution \theta.
Wow! Thanks, but what does that 'high symmetry' here signify?
 
ajay.05 said:
Wow! Thanks, but what does that 'high symmetry' here signify?

The current flows in the cylindrical surface, long rectangular plane, straight wire, or any other geometrical shapes that will give you circular loops of the magnetic field. Normally, the current is normal to a cross-sectional area at any time and it passes through the loops around which the magnetic field is created.
 

Similar threads

Replies
4
Views
1K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
4
Views
2K
Replies
1
Views
1K
Replies
10
Views
2K
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
9K
Replies
8
Views
1K
Replies
8
Views
2K