Magnetic field in a multi-layered solenoid

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SUMMARY

The discussion centers on calculating the minimum number of winding layers required for a solenoid to produce a magnetic induction field of 1 Tesla using 300 µm diameter wire and a maximum current of 10 A. The formula used is B = μ₀ × n × I, leading to the conclusion that one layer produces approximately 0.042 Tesla. Consequently, to achieve 1 Tesla, approximately 24 layers are necessary after correcting an initial miscalculation of 238 layers. This calculation is essential for designing effective electromagnets in various applications.

PREREQUISITES
  • Understanding of electromagnetic theory, specifically solenoid design
  • Familiarity with the formula for magnetic induction (B = μ₀ × n × I)
  • Knowledge of wire specifications, including diameter and current capacity
  • Basic grasp of unit conversions, particularly between Tesla and other magnetic field units
NEXT STEPS
  • Research the effects of wire gauge on solenoid performance
  • Explore advanced solenoid design techniques for higher magnetic fields
  • Learn about the applications of solenoids in electromagnetism
  • Investigate the impact of current variations on magnetic field strength
USEFUL FOR

Engineers, physicists, and students involved in electromagnet design, as well as anyone interested in the practical applications of solenoids in technology and research.

maximus123
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Hello everyone, this is probably a simpler problem than I think but here it is
You are designing an electromagnet capable of producing a magnetic induction field of 1 T
by winding a solenoid around a long cylinder. A solenoid is typically wound by starting
at one end of the cylinder and placing loop after loop directly next to each other. Once
the other end of the cylinder is reached the first winding layer of the solenoid is complete
and the next layer is started by again placing loop after loop next to each other. You are
using 300 \mum diameter wire and the current needed to reach 1 T should not exceed 10 A.
What is the minimum number of winding layers required?

My argument is that the length of the solenoid is the number of turns times the diameter of the wire so

<br /> B=\mu_{0}\times n\times I\\\\<br /> =\mu_{0}\times \frac{N}{L}\times I\\\\<br /> =\mu_{0}\times \frac{N}{N\times d}\times I\\\\<br /> =\mu_{0}\times \frac{1}{d}\times I\\\\<br /> B=4\pi\times 10^{-7}\times\frac{1}{300\times 10^{-6}}\times 10 = 0.042\textrm{ T}<br />
So one layer gives 0.042 Tesla so to get 10 Tesla you'd need 10/0.042\approx 238 layers.

I don't have a great deal of confidence in this argument but I'm struggling to see how else to approach this question. Any help would be greatly appreciated. Thanks.
 
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1 Tesla, not 10.
Looks good.
 
Ah yes, silly mistake, so 23.8 layers, i.e 24 layers.
 

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