Magnetic Field of 10cm Square Loop w/ 0.3A Current

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Homework Help Overview

The problem involves calculating the magnetic field at the center of a square loop of wire with a side length of 10 cm carrying a current of 0.3 A. The discussion centers around the appropriate equations and methods for determining the magnetic field generated by the loop.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore various equations related to magnetic fields, questioning their validity and applicability to the problem. There is discussion about calculating the magnetic field from individual segments of the loop and how to combine these results. Some participants express uncertainty about the area needed for calculations.

Discussion Status

The discussion is active with participants sharing different equations and interpretations. Some guidance has been offered regarding the calculation of the magnetic field from segments of the loop, but there is no explicit consensus on the correct approach or final equation yet.

Contextual Notes

Participants mention needing to determine the area to calculate the magnetic constant, indicating that some information may be missing or unclear. There is also a reference to external resources for clarification.

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Homework Statement


A square loop of wire with a side of 10cm carries a current of 0.3A. What is the
magnetic field in the center of the square loop?


Homework Equations



B= 2([tex]\sqrt{}[/tex]2)[tex]\mu[/tex]I/[tex]\pi[/tex]L

[tex]\mu[/tex]=IA


The Attempt at a Solution



Not sure if these are the right equations for this problem and if they aren't then I have no idea what to do. If they are then I just need to know what the area would be.
 
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Can you find a magnetic field created by 1 segment of a loop? It is similar to finding a magnetic field caused by long wire with current I.
 
B= [tex]\mu[/tex]I/ 2[tex]\pi[/tex]a

Is this right?
 
sqrt(2), i think.
 
so B= ([tex]\sqrt{}[/tex]2)[tex]\mu[/tex]I/2[tex]\pi[/tex]a ?
 
It is just a magnitude of field due to 1 segment of a loop. Multiply it with 4. :)
 
ok so that equation times 4. Thanks
 
oh and I'm still not really sure what the area would be, I need it to figure out what [tex]\mu[/tex] is.
 
  • #10
oh yeah, I forgot about that. Thanks again.
 

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