What is the Force per Meter on Conductor C in a Three-Phase Transmission Line?

Click For Summary
In a three-phase transmission line with conductors A, B, and C arranged in an equilateral triangle, conductors A and B carry 75A while conductor C carries a return current of 150A. The discussion focuses on calculating the force per meter on conductor C due to the magnetic fields generated by conductors A and B. Participants suggest using the magnetic field equations and the force equation F = i∫(B×dl) to determine the forces acting on conductor C. There is confusion regarding how the current in conductor C affects the magnetic field and whether it cancels out the contributions from A and B. The conversation emphasizes the need to clarify the interactions between the currents and the resulting magnetic fields to solve the problem accurately.
formulajoe
Messages
177
Reaction score
0
a three phase transmission line consists of three conductors that are supported at points A,B, c to form an equilateral triangle. At one instant, conductors A and B both carry a current of 75A while conductor C carries a return current of 150 A. Find the force per meter on conductor C at that instant.

heres what it looks like

A
|
|
|-------C
|
|
B


current at A and B is going in, current at C is coming out. Each point is 2 meters apart.

This is the z = 0 plane
im really stuck on this one.
 
Physics news on Phys.org
Where are you stuck, what have you tried?

Spit out some equations you think might fit.
 
the only think i can think of is to find the H field about A and B with rho being equal to the distance to C. than use the int(i*dl cross B). do that at A and B ? i don't see how the 150 amp current causes a force at C.
 
The force on a charge due to magnetic field from each wire will be:

F = i\int{B\times dl}

Now you'll want to find the force for wires A and B at point C. Does the current through C affect the magnetic field? How so?
 
since the current at C is twice at the current at A and B than wouldn't that cancel out the magnetic field?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 40 ·
2
Replies
40
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 15 ·
Replies
15
Views
1K
  • · Replies 23 ·
Replies
23
Views
5K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 27 ·
Replies
27
Views
3K
  • · Replies 25 ·
Replies
25
Views
2K
  • · Replies 15 ·
Replies
15
Views
6K
Replies
1
Views
2K