What is the Force per Meter on Conductor C in a Three-Phase Transmission Line?

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SUMMARY

The discussion revolves around calculating the force per meter on conductor C in a three-phase transmission line configuration, where conductors A and B carry 75A each, and conductor C carries a return current of 150A. The conductors are arranged in an equilateral triangle, with each point spaced 2 meters apart. The relevant equation for determining the force on conductor C is F = i∫(B × dl), where the magnetic field B is influenced by the currents in conductors A and B. The participants explore the interaction of the magnetic fields and currents, particularly how the return current in conductor C affects the overall magnetic field and resultant force.

PREREQUISITES
  • Understanding of three-phase transmission line configurations
  • Knowledge of electromagnetic theory, specifically the Biot-Savart Law
  • Familiarity with vector calculus and cross products
  • Ability to apply Ampère's Law in practical scenarios
NEXT STEPS
  • Study the Biot-Savart Law and its application in calculating magnetic fields
  • Learn about the forces between parallel conductors carrying current
  • Research the implications of return currents in three-phase systems
  • Explore the effects of conductor spacing on electromagnetic interactions
USEFUL FOR

Electrical engineers, students studying power systems, and professionals involved in the design and analysis of transmission lines will benefit from this discussion.

formulajoe
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a three phase transmission line consists of three conductors that are supported at points A,B, c to form an equilateral triangle. At one instant, conductors A and B both carry a current of 75A while conductor C carries a return current of 150 A. Find the force per meter on conductor C at that instant.

heres what it looks like

A
|
|
|-------C
|
|
B


current at A and B is going in, current at C is coming out. Each point is 2 meters apart.

This is the z = 0 plane
im really stuck on this one.
 
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Where are you stuck, what have you tried?

Spit out some equations you think might fit.
 
the only think i can think of is to find the H field about A and B with rho being equal to the distance to C. than use the int(i*dl cross B). do that at A and B ? i don't see how the 150 amp current causes a force at C.
 
The force on a charge due to magnetic field from each wire will be:

F = i\int{B\times dl}

Now you'll want to find the force for wires A and B at point C. Does the current through C affect the magnetic field? How so?
 
since the current at C is twice at the current at A and B than wouldn't that cancel out the magnetic field?
 

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