Magnetic Field -- Some help with the right hand rule please

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SUMMARY

The discussion focuses on applying the right-hand rule to determine the direction of the magnetic force on an electron moving in a magnetic field of 0.0200 T. The initial magnetic force calculated is 1.16 x 10^-14 N, with the electron's velocity directed north. The user correctly identifies that the magnetic force direction is east, based on the right-hand rule, which involves pointing the thumb in the direction of velocity and fingers in the direction of the magnetic field. Additionally, the radius of the electron's circular path is calculated to be 1.4 x 10^-3 m.

PREREQUISITES
  • Understanding of the Lorentz force equation: F=qvB
  • Familiarity with vector cross products
  • Knowledge of magnetic fields and forces
  • Basic principles of electron motion in magnetic fields
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  • Study the vector version of the Lorentz force in detail
  • Learn about the right-hand rule applications in electromagnetism
  • Explore the relationship between magnetic fields and charged particle motion
  • Investigate the effects of different magnetic field strengths on electron trajectories
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Mary1910
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Homework Statement



A magnetic field of 0.0200 T (up) is created in a region.

a) Find the initial magnetic force on an electron initially moving at 5.00 x 10^6 m/s (N) in the field.

b) What is the radius of the circular path? Make a sketch showing the path of the electron.

Homework Equations



F=qvB

r=mv / qB

The Attempt at a Solution


a)
I have already determined that a) is 1.16 x 10^-14 N, my question is how do I use the right hand rule to determine direction? Since the velocity is (N) I point my thumb north and since B is (up) I have been pointing my fingers upwards. Therefore my palm is pushing East. Is this correct?b)
I found that r=1.4 x 10^-3 m so the magnetic force for also be (East)??

Some help with the right hand rule, specifically to this question would be appreciated.
 
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Are you familiar with the vector version of the Lorentz force? That helps me keep the Right-Hand Rule straight. So "X" represents the vector cross product:

F = qV X B

So first of all, remember that this question is about an electron, so qV is negative, or in the opposite direction from V. Does that make sense?

Second, The way I use the cross product is to curl my fingers from the first term vector to the second term vector, and the resultant vector is in the direction of my thumb. So If I curl my fingers from the qV direction (which is which way?) to the B vector direction, which direction is my right thumb pointing in? :smile:
 

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