Magnetic Fields from Two Infinite Sheets of Current Problem

Click For Summary
The discussion revolves around calculating the magnetic field integral, ∫B * dl, for two infinite sheets of current. Each sheet has a different current density, with the left sheet carrying 2.3 A and the right sheet 4.2 A. Participants suggest using the principle of superposition to find the magnetic field contributions from each sheet separately, noting that the line integral is independent of currents outside the loop. There is confusion regarding the correct rectangle for the line integral, as well as the relevance of the currents from both sheets. Ultimately, the focus is on determining the magnetic field along the specified segment, emphasizing the need to consider only the current enclosed by the loop.
Gee Wiz
Messages
137
Reaction score
0

Homework Statement



Two infinite sheets of current flow parallel to the y-z plane as shown. The sheets are equally spaced from the origin by xo = 4.2 cm. Each sheet consists of an infinite array of wires with a density n = 16 wires/cm. Each wire in the left sheet carries a current I1 = 2.3 A in the negative z-direction. Each wire in the right sheet carries a current I2 = 4.2 A in the positive z-direction.

What is
∫B *dl
where the integral is taken along the dotted line shown, from a to b. H is 11.7cm.

Homework Equations



∫B *dl (it's a dot product)

The Attempt at a Solution



I'm not really sure how to start this problem. I thought about finding the current enclosed, because that is what i did for a similar problem, but there isn't any current enclosed. Would both sheets of current be affecting this segment? I think so, and i know they would be acting in opposite directions (using the right hand rule at those locations). I also thought that i could ignore the horizontal distance between a and b since i thought that would be perpendicular to dl.
https://www.smartphysics.com/Content/Media/Images/EM/15/h15_sheets.png
 
Last edited by a moderator:
Physics news on Phys.org
Of course there is current enclosed, just look at those x inside the trapezoid! But you are correct that this method won't work. Because the other sheet is there, you won't be able to find B by a symmetry argument.

However, if there was only one sheet then you may be able to do it.

I suggest you use something called superposition. In other words, B = B from sheet 1 + B from sheet 2. So first figure the B field from just one sheet.
 
But, this question isn't talking about the trapezoid. It only wants the segment from a to b. I tried doing 4.2(current from right sheet) minus 2.3(the current from the left sheet) times 16*11.7, to get a current enclosed. But the enclosed terminology didn't seem to apply here.
 
Also, I think that all the contributions to the segment would be vertical components since the sheets are infinite.
 
Like I wrote before, first consider only one sheet and find the B field everywhere outside that single sheet.
 
Okay, so then would i use Iu/(2pi*r)? to find the b field at that distance away. But then if i do that what do i select as my r, since a and b are not at an equal distance. I'm thinking a, because if i draw a triangle the vertical component is at h, which is the same distance as a is from the sheet.
 
Try to find the B field of a single sheet. This is due to a bunch of currents at different distances. You could try and use the Biot–Savart law, but there is an easier way. You can just assume that the B field is parallel to the sheet everywhere (and perpendicular to the current).
 
Okay so i guess I'm blanking on how to find the b-field for a single sheet. I thought my only two equations to find the b field were biot-savart and the integral of b*dl
 
So, try the second one, ∫bdl! I suggest you try a rectangular path.
 
  • #10
MisterX said:
Of course there is current enclosed, just look at those x inside the trapezoid! But you are correct that this method won't work. Because the other sheet is there, you won't be able to find B by a symmetry argument.

The line integral is independent of whatever current lies outside the loop. The answer is μI where I is the current enclosed.
please refer to Fundamentals of Physics by Halliday and Resnick
 
  • #11
So, i tried to do make the rectangle with h as my height for both sheets. I did 11.7*16 to get the number of wires enclosed times 2.3 and 4.2 for the respected sheets. I subtracted the two values and then multiplied by u, but this wasn't correct. So I am thinking that i didn't make the correct rectangle..
 
  • #12
Gee Wiz said:
I did 11.7*16 to get the number of wires enclosed times 2.3 and 4.2 for the respected sheets.

you don't need to include the current I_2 as it is not within the loop. Is the answer 5.4\times10^{-4}?
 
  • #13
That was the answer to an earlier question, when it asked for the B-field within the trapezoid, but this one is only asking for the field along the line segment. As far as i can tell, it doesn't really include and current.
 

Similar threads

Replies
2
Views
1K
  • · Replies 5 ·
Replies
5
Views
8K
Replies
4
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
Replies
2
Views
1K
Replies
16
Views
1K
  • · Replies 15 ·
Replies
15
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K