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## Homework Statement

The magnetic field strength at the South Pole is around 66μT, and magnetic field lines point out of the earth perpendicular to the surface. The sled is a metal square of side 0.95 m (with non-conducting wooden slats in between).

What is the magnetic flux through the sled sitting flat on the ground?

Imagine that you accidentally flip the sled from horizontal to vertical in 0.65 s. What is the induced emf in the sled as a result of that motion?

## Homework Equations

B = 0.66 x 10^-3 T + z direction

A = (0.95m)^2 = 0.9025 m

θ = 90° (?)

Phi = B * nA = BAcosθ = B

_{n}A

ε = -dPhi/dt

## The Attempt at a Solution

I tried using the flux equation with cos(90), but since that's 0, would the flux really be 0?? Or is it just B*A?

Same problem with induced emf, but how do I calculate the derivative?

Thanks!