Magnetic force, coefficient of friction, forces in equilibrium

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SUMMARY

The discussion focuses on determining the magnitude and angle of the smallest magnetic field required to prevent a 1.0 kg copper rod, carrying a current of 50 A, from sliding on horizontal rails with a coefficient of static friction of 0.60. The relationship between the magnetic force and the forces acting on the rod is established using the equation μmg = iLBsin(θ). Participants emphasize the importance of creating a free-body diagram to accurately identify all forces acting on the rod, which is crucial for solving for the magnetic field strength (B) and angle (θ).

PREREQUISITES
  • Understanding of magnetic forces and their calculations
  • Knowledge of static friction and its coefficients
  • Familiarity with current-carrying conductors in magnetic fields
  • Ability to draw and interpret free-body diagrams
NEXT STEPS
  • Study the Lorentz force law and its applications in magnetic fields
  • Learn about the principles of static friction and its role in equilibrium
  • Explore the concept of magnetic fields generated by current-carrying wires
  • Practice drawing free-body diagrams for various physical scenarios
USEFUL FOR

Physics students, electrical engineers, and anyone interested in the dynamics of forces in equilibrium involving magnetic fields and friction.

wushumaster
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A 1.0 kg copper rod rests on two horizontal rails 1.0 m apart and carries a current of 50 A from one rail to the other. The coefficient of static friction between rod and rails is 0.60. What are the (a) Magnitude and
(b) Angle (relative to the vertical) of the smallest magnetic field that puts the rod on the verge of sliding?

I can get what B times sin theta is by setting mu times mg = iLBsin theta, but how to get B or theta?
 
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wushumaster said:
A 1.0 kg copper rod rests on two horizontal rails 1.0 m apart and carries a current of 50 A from one rail to the other. The coefficient of static friction between rod and rails is 0.60. What are the (a) Magnitude and
(b) Angle (relative to the vertical) of the smallest magnetic field that puts the rod on the verge of sliding?

I can get what B times sin theta is by setting mu times mg = iLBsin theta, but how to get B or theta?
Before we go farther with this, I don't think this equation is correct. Have you drawn a free-body or force diagram for the rod? Since it can be difficult to post a figure here, I'll just ask you to list here all the forces acting on the rod -- and you should still draw a force diagram for yourself.
 

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