Electric forces between conducting rod and rail

Click For Summary
SUMMARY

The discussion revolves around the electric forces between a conducting rod and a rail when both carry current in opposite directions. The participants utilize the right-hand grip rule and left-hand rule to deduce that a magnetic force acts vertically upwards on the rod due to the magnetic field generated by the current in the rail. To maintain equilibrium at height H, the forces produced by both the rod and the wire must be equal, leading to the conclusion that the magnetic force formula F = BIL sin θ applies to both. The inquiry focuses on deriving the current (I) in terms of mass (m) and length (L) while maintaining equilibrium.

PREREQUISITES
  • Understanding of electromagnetic theory, specifically the right-hand grip rule and left-hand rule.
  • Familiarity with the formula for magnetic force, F = BIL sin θ.
  • Knowledge of equilibrium conditions in physics.
  • Basic concepts of current (I) and its relationship with magnetic fields.
NEXT STEPS
  • Study the derivation of the magnetic force formula F = BIL sin θ in detail.
  • Learn about the principles of electromagnetic equilibrium and stability.
  • Explore the application of the right-hand grip rule and left-hand rule in various electromagnetic scenarios.
  • Investigate the relationship between current, mass, and length in conducting systems.
USEFUL FOR

Physics students, electrical engineers, and anyone interested in understanding the principles of electromagnetism and the behavior of conducting materials in magnetic fields.

jisbon
Messages
475
Reaction score
30
Homework Statement
A rod of length L and mass m can slide on vertical rails and is height H above a wire when both carry the same current I in opposite directions. If current in the lower wire is suddenly doubled, what is the initial acceleration of rod?
Relevant Equations
-
1569379091181.png

Alright, to start off:

I'm not even sure how this works in the first place. What I do understand is that if they carry current in the opposite direction, using right-hand grip rule, the magnetic field between them will be the same (into the page). Hence using the left-hand rule, I can deduce that there is a magnetic force produced from the wire and rail vertically upwards (in this correct?)
So to remain the at equilibrium at height H, both rod and wire must produce the same force (is this correct?)
However searching through my notes and stuff, I found out both wire and rods to have the same formula for magnetic force ###(F=BIL sin \theta)##

Not sure how to proceed on here, what's the 'theory' behind this question? Any guidance will be appreciated. Thank you!
 
Physics news on Phys.org
Realized this question was similar to the one I posted few weeks back. I'm supposed to find I in terms of m and L. Since the rod remains in equilibrium at height L, is it ok to assume then ##\epsilon =(\mu_{0}I/2\pi L)(L)(0)##
I'm not sure how to find the current if its equlibirum
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
Replies
44
Views
5K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
7
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
6
Views
3K
Replies
1
Views
2K