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Magnetic force of a falling ball

  1. Jun 29, 2009 #1
    1. The problem statement, all variables and given/known data

    A metal ball having net charge 4.5 × 10−6 C
    is thrown out of a window horizontally at a
    speed 43 m/s. The window is at a height
    63 m above the ground. A uniform horizon-
    tal magnetic field of magnitude 0.071 T is
    perpendicular to the plane of the ball’s tra-
    jectory.
    The acceleration of gravity is 9.8 m/s2 .
    Find the magnitude of the magnetic force
    acting on the ball just before it hits the
    ground. Answer in units of N.

    2. Relevant equations

    F=QVB
    V=sqrt(2*g*H)


    3. The attempt at a solution

    i enterd the given values and solved for v and then re-enterd the answer in the force equation but my final solution is wrong dont why .. can somone explain were im going wrong

    thanx
     
  2. jcsd
  3. Jun 29, 2009 #2

    Doc Al

    User Avatar

    Staff: Mentor

    This gives the vertical component of velocity, but don't forget about the horizontal component. (In the force equation, you need the total velocity.)
     
  4. Jun 29, 2009 #3
    which is the initial velocity given in the equation
     
  5. Jun 29, 2009 #4
    what i did
    is that i added the Vo + sqrt(2gh) .. then i multilpied it by the charge and the nagnetic field

    is that what you meant !
     
  6. Jun 29, 2009 #5
    finish i figured it out thanx alot
     
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