Magnetic forces on two current carrying wires

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To find the force per unit length on two parallel wires carrying different currents, the magnetic field generated by one wire is used to calculate the force on the other. The correct formula for the force per unit length is F/L = (μ₀ * I₁ * I₂) / (2π * d), where d is the distance between the wires. For the given currents of 2.0 A and 4.0 A at a distance of 0.24 m, the total force per unit length is 6.7 * 10^-6 N/m, indicating an attractive force. The initial calculations incorrectly treated the magnetic field contributions from each wire separately, leading to confusion about differing forces. The final consensus confirms that the forces are indeed equal and attractive, despite the different currents.
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"Find the force per unit length on each of two long, straight, parallel wires that are 24 cm apart when one carries a current of 2.0 A and the other a current of 4.0 A in the same direction."

Tell me if I'm doing this right:
I use d = 0.24m, and the equations B = (mag. perm. * I)/(2*pi*d), and F = ILB.

The force per unit length on each wire is then: F/L = IB.

Plugging in I and B for each of the wires, I get:
F/L (for the 2.0A wire) = 3.3 * 10^-6 N/m (toward the other wire)
F/L (for the 4.0A wire) = 1.3 * 10^-5 N/m (toward the other wire)

I think it's wrong because the answer is supposedly: "6.7 * 10^-6 N/m; attractive". But I would think that the forces are different on each wire, because the wires are carrying different currents...
 
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Your formulae are correct, however I can't see how you obtained your two different answers.
Remember, the expression you wrote explicitly is
\frac{\mu_0I_1I_2}{2\pi d}

Can you possibly have two different answers ? :)
 
oh ooops.
I did (F/L)1 = I1B1, not I1B2!
 
Thought so :biggrin:
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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