Magnetic Induction and Magnetic Field

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SUMMARY

The discussion focuses on the distinction between magnetic field and magnetic induction in the context of a solenoid and a wire loop problem. The Biot-Savart law is utilized to derive the magnetic field, leading to the equation B = (μ₀ I)/(4πs) ∫ cos θ dθ. The magnetic field at the center of the loop is calculated as B = (√2 μ₀ I)/(πR), but the participant seeks clarification on the correct equation for magnetic induction. The confusion arises from the terminology, as magnetic field is often referred to as magnetic induction in older texts.

PREREQUISITES
  • Understanding of Biot-Savart law
  • Familiarity with magnetic fields and induction concepts
  • Knowledge of solenoid magnetic field equations
  • Basic calculus for evaluating integrals
NEXT STEPS
  • Research the differences between magnetic field and magnetic induction
  • Study the application of the Biot-Savart law in various geometries
  • Learn about the Ampère's law and its relation to magnetic fields
  • Explore practical applications of solenoids in electromagnetic devices
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Students studying electromagnetism, physics educators, and anyone seeking to clarify concepts related to magnetic fields and induction in electrical engineering contexts.

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Homework Statement



I would appreciate some help with the following problem:

http://img407.imageshack.us/img407/7647/questionb.jpg

Homework Equations



This is an equation derived from Biot-Savart law:

[itex]B= \frac{\mu_0 I}{4 \pi s} \int^{\theta_2}_{\theta_1} cos \theta d \theta = \frac{\mu_0 I}{4 \pi s} (sin \ \theta_2 - sin \ \theta_1)[/itex]

Magnetic field of a solenoid: [itex]B= \mu_0 \frac{N}{l} I[/itex]

N is the number of turns.

Magnetic field of a solenoid

The Attempt at a Solution



(a) Using the above equation above with R=L/2, θ2=-θ1=45°, and remembering that there are 4 sides, we find the magnetic field to be

[itex]B=\frac{\sqrt{2} \mu_0 I}{\pi R}[/itex]

However this gives the "magnetic field" at the center of the loop, not the "magnetic induction". So, what exactly is the difference between magnetic induction and field? And what equation do I have to use in order to find the magnetic induction?

(b) Since the system forms a kind of solenoid I use the equation for the magnetic field of solenoid:

The total length og the wire is 20cmx4=80cm, 100x80=80000cm. So

(4∏x10-7) (1/8) I = 50x10-6

Solving for current yields I= 318.6 A. This value seems too large to be realistic. And the question again asks for magnetic induction, not the field. What equation do I have to use here? :confused:
 
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Magnetic Field is sometimes called "Magnetic induction" - particularly in older textbooks.

(a) I'm puzzled that you used the polar form for the integral, since your problem has rectangular symmetry.

(b) You could also use the result from part (a) to help you.
 

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