Magnetig flux of a straight conductor

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Homework Help Overview

The discussion revolves around calculating the magnetic flux of a straight conductor, specifically using the formula for the magnetic field and the relationship for magnetic flux. Participants are exploring how to approach the integration of the magnetic flux over a non-rectangular area.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need to integrate the magnetic flux and question whether to treat the area as a whole or divide it into sections. There is mention of using symmetry to simplify the integration process.

Discussion Status

Some participants suggest dividing the area into three sections for integration, considering different ranges along the wire. There is an acknowledgment of the potential for symmetry to aid in the calculations, but no consensus on the exact approach has been reached.

Contextual Notes

Participants are navigating the complexities of integrating over a non-standard area and are considering how to effectively set up their integrals based on the geometry involved.

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Homework Statement



http://www.aijaa.com/img/b/00815/3678868.jpg

Homework Equations



[tex]B= \frac { \mu _0}{2 \pi r}I[/tex]
[tex]d \phi = \vec{B} \cdot d \vec {A}[/tex]

The Attempt at a Solution



I know the magnetic field of the conductor is [tex]B= \frac { \mu _0}{2 \pi r}I[/tex]. And in order to solve the magnetic flux I need to integrate [tex]d \phi = \vec{B} \cdot d \vec {A}[/tex]. But the question is, since the area is not square or rectangular, can I simply integrate over the whole area at once or do I need to cut the integral into pieces?
 
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Kruum said:

Homework Statement



Homework Equations



[tex]B= \frac { \mu _0}{2 \pi r}I[/tex]
[tex]d \phi = \vec{B} \cdot d \vec {A}[/tex]

The Attempt at a Solution



I know the magnetic field of the conductor is [tex]B= \frac { \mu _0}{2 \pi r}I[/tex]. And in order to solve the magnetic flux I need to integrate [tex]d \phi = \vec{B} \cdot d \vec {A}[/tex]. But the question is, since the area is not square or rectangular, can I simply integrate over the whole area at once or do I need to cut the integral into pieces?

You will have different ranges along the wire that you will need to consider in the integral. Symmetry should make it easier to account for.

Let's consider this Introductory still?
 
LowlyPion said:
You will have different ranges along the wire that you will need to consider in the integral. Symmetry should make it easier to account for.

So what your saying is, that I should divide the cross into three pieces and integrate them separately? So the first integral would be from r to r+b over the area of ab. The second from r+b to r+b+a over the area of (a+2b)a. And the third one from r+b+a to r+2b+a over the area of ab.
 
Kruum said:
So what your saying is, that I should divide the cross into three pieces and integrate them separately? So the first integral would be from r to r+b over the area of ab. The second from r+b to r+b+a over the area of (a+2b)a. And the third one from r+b+a to r+2b+a over the area of ab.

3 rectangles sounds good to me.

Slice them horizontally or vertically, which ever way your Ginsu slices the easiest.
 
Thank you!
 

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