MHB Magnitude and angle of vector sum

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To find the magnitude of the resultant force and its angle with the positive x-axis, first determine the x and y components of each force using trigonometric functions. The 200 N force has components of 100 N in the y-direction and 100 N in the x-direction, while the 300 N force is purely in the negative x-direction. Sum the x-components and y-components separately to find the resultant vector's components. The magnitude is calculated using the Pythagorean theorem, and the angle is derived using the inverse tangent function, adjusting for the correct quadrant if necessary. The final angle with the positive x-axis is approximately 139.1 degrees.
  • #31
I thought this was a standard physics question in which the answer would have been 40.9 or 49.1, but I just re-read the question: "angle it makes with the positive x-axis." So yes, your answer was what they were looking for :D
 
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  • #32
ineedhelpnow said:
Rido the back of the book says 139.1 (Dull) lol

I only read:

Rido12 said:
So yes, 139.1 is right

(Rofl)
 
  • #33
@ILS lol you're hilarious

@Rido but wouldn't the answer be 139 no matter what because it was -41. not 41. i suppose the answer could be left as -1 but that's the same as 139 (Wondering)
 
  • #34
(Giggle)
@ILS
It's been a while since I actually read the question, so I was convinced 40.1 was the right answer...so while I was writing my answer, I realized that I got 139.1 too (Rofl) But I was too lazy to erase what I had already said (Nod)

@ineedhelpnow, in physics, they don't care about the angle 139.1. they care more about the related acute angle from the horizontal or vertical axis. The related acute is a positive angle.
 
  • #35
Rido12 said:
(Giggle)@ineedhelpnow, in physics, they don't care about the angle 139.1. they care more about the related acute angle from the horizontal or vertical axis. The related acute is a positive angle.

it shouldn't be much of a surprise when i say that I am terrible at physics... (Blush)
 

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